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aev [14]
3 years ago
7

If an object is propelled upward from a height of s feet at an initial velocity of v feet per​ second, then its height h after t

seconds is given by the equation hequals=minus−16t squaredt2plus+vtplus+​s, where h is in feet. if the object is propelled from a height of 88 feet with an initial velocity of 6464 feet per​ second, its height h is given by the equation hequals=minus−16t squaredt2plus+6464tplus+88. after how many seconds is the height 3636 ​feet?
Mathematics
1 answer:
julsineya [31]3 years ago
3 0
Im sorry i have no idea i think it would be half the time of 6464 ft per second
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