Question

Evaluate the function at each specified value of the independent variable and simplify. (if an answer is undefined, enter undefined.) h(t) = t2 − 8t (a) h(8) (b) h(1.8) (c) h(x + 8

Answer 1

For this case we have the following function:

$h (t) = t ^ 2 - 8t$

What we should do is evaluate the function for the different values of the independent variable.

We have then:

For x = 8:

$h (8) = (8) ^ 2 - 8 (8)$

$h (8) = 64 - 64$

$h (8) = 0$

For x = 1.8:

$h (1.8) = (1.8) ^ 2 - 8 (1.8)$

$h (1.8) = 3.24 - 14.4$

$h (1.8) = -11.16$

For x = x + 8:

$h (x + 8) = (x + 8) ^ 2 - 8 (x + 8)$

$h (x + 8) = x ^ 2 + 16x + 64-8x-64$

$h (x + 8) = x ^ 2 + 18x$

Answer:

The results of evaluating the function are:

$h (8) = 0$

$h (1.8) = -11.16$

$h (x + 8) = x ^ 2 + 18x$