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madam [21]
2 years ago
15

Evaluate the function at each specified value of the independent variable and simplify. (if an answer is undefined, enter undefi

ned.) h(t) = t2 − 8t (a) h(8) (b) h(1.8) (c) h(x + 8
Mathematics
1 answer:
tekilochka [14]2 years ago
5 0

For this case we have the following function:

h (t) = t ^ 2 - 8t

What we should do is evaluate the function for the different values of the independent variable.

We have then:

For x = 8:

h (8) = (8) ^ 2 - 8 (8)

h (8) = 64 - 64

h (8) = 0

For x = 1.8:

h (1.8) = (1.8) ^ 2 - 8 (1.8)

h (1.8) = 3.24 - 14.4

h (1.8) = -11.16

For x = x + 8:

h (x + 8) = (x + 8) ^ 2 - 8 (x + 8)

h (x + 8) = x ^ 2 + 16x + 64-8x-64

h (x + 8) = x ^ 2 + 18x

Answer:

The results of evaluating the function are:

h (8) = 0

h (1.8) = -11.16

h (x + 8) = x ^ 2 + 18x

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Step-by-step explanation:

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Step-by-step explanation:

open the bracket

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3 years ago
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Which expression is equal to 4/8
givi [52]
<h2>Fractions</h2>

Which expression is equal to \large\tt \frac{4}{8}?

Option 1

  • \large \tt 4  \times \frac{1}{2}  =  \frac{4}{1}  \times  \frac{1}{2}  =   \red{\frac{4}{2}}

Option 1 is not equal to \large\tt \frac{4}{8}

\huge{\overline{\qquad\qquad\qquad\qquad \: \: \: }}

Option 2

  • \large \tt 3 \times  \frac{1}{5}  =  \frac{3}{1}  \times  \frac{1}{5}  =   \red{\frac{3}{5}}

Option 2 is not equal to \large\tt \frac{4}{8}

\huge{\overline{\qquad\qquad\qquad\qquad \: \: \: }}

Option 3

  • \large \tt 3  \times \frac{1}{8}  =  \frac{3}{1} \times  \frac{1}{8}   =   \red{\frac{3}{8}}

Option 3 is not equal to \large\tt \frac{4}{8}

\huge{\overline{\qquad\qquad\qquad\qquad \: \: \: }}

Option 4

  • \large \tt 4  \times \frac{1}{8}  =   \frac{4}{1}  \times  \frac{1}{8}  =   \green{\frac{4}{8}}

Therefore, option 4 is equal to \large\tt \frac{4}{8}

\huge{\overline{\qquad\qquad\qquad\qquad \: \: \: }}

<h3>#CarryOnLearning</h3>
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Hitman42 [59]

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y=-5x

Step-by-step explanation:

take two points, I took 0,4 and 1-,1 and do

y2-y1 over x2-x1

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2 years ago
Please answer quickly I only have 5 mins lol. The ratio of students polled in 6th grade who prefer lemonade to Iced tea is 8:4,
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Answer:

Let total students who prefer lemonade is 2a and who prefer ice tea is a.

Students in 6th grade=39

2a+a=39

3a=39

a=39/3

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and those who prefer ice tea is 2a=26

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2 years ago
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