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vivado [14]
3 years ago
10

I don't understand! I need help.

Mathematics
2 answers:
trasher [3.6K]3 years ago
6 0
A scalene triangle has 3 unequal sides, so none of the sides are the same. A right triangle has one angle that is 90°, which is indicated by a little square. An isosceles triangle has 2 equal sides (it looks like an ice cream cone). And an equilateral triangle has 3 sides that are all the same.
solmaris [256]3 years ago
4 0
Ok so for number 1 when you see it with three different set of lines it is scalene. When you see one like number two with two of the same set of lines it is isosceles. When you see one with all three of the same set of lines it is equilateral. So the answers would be 1.d, 2.b, 3.b, 4.a
A way to remember this is for isosceles think of it as eyes you have two eyes that are alike. For equilateral all parts are equal. Scalene as a scale(the numbers can be all over the place am I right) for a right triangle it has to have one corner at a 90 degree angle so it makes a square.
Brainliest?
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The measure of an angle is 4y. Find the measure of its complement.
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Hello, may I please have some help on these 4 questions? Thanks very much! {Also, if you could answer them quick, that would be
wlad13 [49]
1.

Parallelogram with base a = 20 in. and height h = 16 in.
Triangle with base a = 20 in. and height b = 8 in.

so:

A = A_P+A_T=a\cdot h+\frac{1}{2}\cdot a\cdot b=20\cdot16+\frac{1}{2}\cdot20\cdot8=320+80=\\\\=\boxed{400\text{ in}^2}

2.

Trapezoid with base b₁ = 14 cm, base b₂ = 4 cm and height h = 10 cm
Triangle with base b₁ = 14 cm and height x = 18 cm - 10 cm = 8 cm

so:

A=A_T+A_\Delta=\frac{1}{2}\cdot(b_1+b_2)\cdot h+\frac{1}{2}\cdot b_1\cdot x=\\\\=&#10;\frac{1}{2}\cdot(14+4)\cdot 10+\frac{1}{2}\cdot 14\cdot8=\frac{1}{2}\cdot18\cdot 10+\frac{1}{2}\cdot 14\cdot8=90+56=\\\\=\boxed{146\text{ cm}^2}

3.

We have three rectangles:

A=A_1+A_2+A_3=1\cdot 4+6\cdot5+18\cdot6=4+30+108=\boxed{142\text{ ft}^2}

4.

Area of a circle:

A_\circ=\pi\cdot r^2=3.14\cdot5^2=3.14\cdot25=78.5 \text{ cm}^2

Area of a rectangle:

A_R=8\cdot 6=48\text{ cm}^2

Area of the shaded region:

A=A_\circ-A_R=78.5-48=\boxed{30.5\text{ cm}^2}


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