9. Two fair dice are rolled. Find the odds of rolling the following sums.

Mathematics

1 answer:

Pavel [41]2 years ago

6 0

(a) 1/12
(b) 3/12=1/4
(c) 2/12 = 1/6
(d) 3/12 + 3/12 = 6/12 = 1/2

I think it’s right ???

You might be interested in

NEED CORRECT ANSWER PLEASE! THANKS:)

-BARSIC- [3]

The answer is B. (2x + 5)(x + 1)You could answer this by expanding each answer until you found one that matched 2x^2 + 7x + 5, but I will only show how the answer expands:
2x × x = 2x^2
5 × x = 5x
2x × 1 = 2x
5 × 1 = 5

So in total those brackets expand to 2x^2 + 7x + 5. I hope this helps!

6 0

3 years ago

Six out of the 12 members of the school choir are boys. In simplest form, what fraction of the choir is boys?

zubka84 [21]

Answer:

1/2

Step-by-step explanation:

3 0

3 years ago

What 2 numbers add to get 2 and multiply to 4

rusak2 [61]

Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x= $\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a}$ so

1x^2-2x+4=0
a=1
b=-2
c=4
x= $\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}$
x= $\frac{ 2+/-\sqrt{4-16} }{2}$
x= $\frac{ 2+/-\sqrt{-12} }{2}$
we have $\sqrt{-12}$ and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x= $\frac{ 2+/-2\sqrt{-3} }{2}$
i= $\sqrt{-1}$
x= $\frac{ 2+/-2i\sqrt{3} }{2}$
x= $1+/-i\sqrt{3}$
x= $1-i\sqrt{3}$ or x= $1+i\sqrt{3}$ (those are the 2 numbers)

6 0

4 years ago

What is -2(x+6)+x? Simplify

andrezito [222]

Answer:

Step-by-step explanation:

-x-12

6 0

3 years ago

If the density of a full can is 1.1g/cc what is it’s mass?

podryga [215]

Density = mass / volume
volume of 1 can = 12 * 40 = 480 cm^3
1.1 = mass / 480

mass = 528 grams Answer

6 0

3 years ago