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Mariulka [41]
3 years ago
13

Graph the system of equation below on a piece of paper what is the solution y=x-1 and y=-2x+5

Mathematics
1 answer:
ANTONII [103]3 years ago
6 0

We are given

First equation:

y=x-1

we can use formula

y=mx+b

slope is m=1

y-intercept is b=-1

Second equation:

y=-2x+5

we can use formula

y=mx+b

slope is m=-2

y-intercept is b=5

Graph:

We can see that

both curves intersect at (2,1)

so, solution is x=2 and y=1.................Answer

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Answer:

f^{-1}(x)=\sqrt[3]{x}-1

Step-by-step explanation:

f(x)=(x+1)^3\\\\y=(x+1)^3\\\\x=(y+1)^3\\\\\sqrt[3]{x}=y+1\\\\y=\sqrt[3]{x}-1\\ \\f^{-1}(x)=\sqrt[3]{x}-1

Graphing both inverses, they will be symmetrical about the line y=x.

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Answer:

True

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Lynn is trying to determine how far away Student B is from the balloon. He decides to use the
kaheart [24]

Answer:

See Explanation

Step-by-step explanation:

<em>The question is incomplete as the image that illustrates the scenario is not given.</em>

<em>However, I can deduce that the question is about a right-angled triangle.</em>

<em>So, I will give a general explanation on how to find each of the side of the triangle, given a side and an angle.</em>

<em />

<u>For triangle A (solve for b)</u>

Using cosine formula.

\cos \theta = \frac{Adjacent}{Hypotenuse}

\cos 60= \frac{5}{b}

Make b the subject

b= \frac{5}{\cos 60}

<u>For triangle B (solve for b)</u>

Using cosine formula.

\sin \theta = \frac{Opposite}{Hypotenuse}

\sin 60= \frac{b}{5}

Make b the subject

b = 5\sin 60

<u>For triangle C (solve for b)</u>

Using cosine formula.

\tan \theta = \frac{Opposite}{Adjacent}

\tan 60= \frac{b}{5}

Make b the subject

b = 5\tan 60

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