Question

One container is filled with a mixture that is 30%acid a second container is filled with a mixture that is 50%acid the second containet is 50%larger than the first and that twocontainers are are emptied into a third what percent of acid is the third container

Answer 1

Answer:

The amount of acid in third container is =42%

Step-by-step explanation:

Given , one container is filled with a mixture that is 30% acid a second container filled with a mixture that is 50% acid and the second container 50% larger than the first .

Let, the volume of first container is = x

Then , the volume of second container = (x+ x of 50%)

                                                                 = x + 0.5 x

                                                                 = 1.5 x

Therefore the amount of acid in first container $=x \times \frac{30}{100}$ = 0.3 x

The amount of acid in second container $=1.5x \times \frac{50}{100}$  = 0.75x

Total amount of acid= 0.3x + 0.75x = 1.05 x

Total amount  of solution = x+1.5x = 2.5x

The amount of acid in third container is = $\frac{1.05x}{2.5x} \times 100%$ %

                                                                     = 42%