Substitute x with the members of the domain.
f(x) = 5x² + 4
Substitute with the domain of -4
f(x) = 5x² + 4
f(-4) = 5(-4)² + 4
f(-4) = 5(16) + 4
f(-4) = 80 + 4
f(-4) = 84
Substitute with the domain of -2
f(x) = 5x² + 4
f(-2) = 5(-2)² + 4
f(-2) = 5(4) + 4
f(-2) = 20 + 4
f(-2) = 24
Substitute with the domain of 0
f(x) = 5x² + 4
f(0) = 5(0)² + 4
f(0) = 5(0) + 4
f(0) = 0 + 4
f(0) = 4
Substitute with the domain of 1.5
f(x) = 5x² + 4
f(1.5) = 5(1.5)² + 4
f(1.5) = 5(2.25) + 4
f(1.5) = 11.25 + 4
f(1.5) = 15.25
Substitute with the domain of 4
f(x) = 5x² + 4
f(4) = 5(4)² + 4
f(4) = 5(16) + 4
f(4) = 80 + 4
f(4) = 84
The range of the function for those domain is {4, 24, 15.25, 84}
The value of four is not greater than five of corse if the value of four were positive and five negative but four is not greater the five.
P = 2(L + W)
P = 50
L = 15
50 = 2(15 + W)
50 = 30 + 2W
50 - 30 = 2W
20 = 2W
20/2 = W
10 = W.....so the width is 10 inches
Answer:
$517.50
WHY?
I used my calculator XDDD
Answer:
sure!
Step-by-step explanation:
1
Multiply the numbers
2
3
⋅
1
5
=
2
1
5
2
3
5
=
2
1
5
Divide the numbers
2
3
5
=
2
1
5
2
1
5
=
2
1
5
Result
2
1
5
=
2
1
5
