(6 to the power of 4 times 2) to power of 3. Equivalent expression
1 answer:
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Answer:
Therefore the given vectors are orthogonal for b = 0,±3.
Step-by-step explanation:
If and
are two vectors orthogonal, then the dot product of
and
will be zero.
i.e
If and
Given two vectors are (-18,b,9) and (b,b²,b)
Let
and
Therefore,
=(-18).b+b.b²+9.b
= -18b+b³+9b
= b³-9b
Since and
are orthogonal. Then
= 0.
Therefore,
b³-9b= 0
⇒b(b²-9)=0
⇒b =0 or b²=9
⇒b=0 or b =±3
Therefore the given vectors are orthogonal for b = 0,±3.