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Karolina [17]
4 years ago
10

Compare the motion of an object acted on by balanced forces with the motion of an object acted on unbalanced forces

Physics
1 answer:
Andrew [12]4 years ago
6 0
When balanced forces act upon an object, the object does not move. But when unbalanced forces act on it, it does. 
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Nimfa-mama [501]
The answer is: An electromagnet is a (Solenoid) with a (metal) core.

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4 years ago
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A 0.0663 kg ingot of metal is heated to 241◦C
Westkost [7]

Answer:280.216j/kg°C

Explanation:

Mass of metal=0.0663kg

mass of water=0.395kg

Final temperature=27.4°C

Temperature of metal=241°C

Temperature of water=25°C

specific heat capacity of water=4186j/kg°C

0.0663xax(241-27.4)=0.395x4186x(27.4-25)

0.0663xax213.6=0.395x4186x2.4

14.16168a=3968.328

a=3968.328 ➗ 14.16168

a=280.216j/kg°C

4 0
3 years ago
Someone help! (i will give u a thanks)
soldier1979 [14.2K]

Answer:

a drummer practicing his drum set

Explanation:

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3 years ago
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A variação no comprimento de uma barra de alumínio foi de 0,0002m. Calcular a variação na temperatura a =22x10-⁶
Furkat [3]

Answer:

1.82°C

Explanation:

presumir inicial comprimento = l₀ = 5 m

dado que:

coeficiente de expansão (α) = 22 x 10⁻⁶, A variação no comprimento (ΔL) = 0.0002 m,

inicial comprimento = l₀ = 5 m

variação na temperatura = ΔT

para Calcular a variação na temperatura,  nós usamos a fórmula:

\Delta L=l_0\alpha \Delta T

substituindo valores:

0.0002=5*22*10^{-6}\Delta T\\\Delta T=\frac{0.0002}{5*22*10^{-6}}\\ 5*22*10^{-6}=1.82^0C

variação na temperatura = 1.82°C

8 0
3 years ago
The amount of energy necessary to remove an electron from an atom is a quantity called the ionization energy, Ei. This energy ca
Verizon [17]

Answer:

The value is E_i  =  1.5596 *10^{-18} \  J

Explanation:

From the question we are told that

The wavelength is \lambda  =  48.2 nm  =  48.2  *10^{- 9 }\  m

The velocity is v = 2.371*10^6 \ m/s

The mass of electron is m_e  =  9.109*10^{-31} \  kg

Generally the energy of the incident light is mathematically represented as

E =  \frac{h *  c}{\lambda}

Here c is the speed of light with value c =  3.0 *10^{8} \  m/s

h is the Planck constant with value h = 6.62607015 *  10^{-34 }  J\cdot s

So

E =  \frac{6.62607015 *  10^{-34 }* 3.0 *10^{8}}{48.2  *10^{- 9 }}

=> E = 4.12 *10^{-18} \  J

Generally the kinetic energy is mathematically represented as

E_k  =  \frac{1}{2} *  m_e * v^2

=> E_k  =  \frac{1}{2} *  9.109*10^{-31} * (2.371*10^6 )^2

=> E_k  =  2.56 *0^{-18} \  J

Generally the ionization energy is mathematically represented as

E_i  =  4.12 *10^{-18} -   2.56 *0^{-18}

=>     E_i  =  1.5596 *10^{-18} \  J

7 0
4 years ago
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