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mash [69]
3 years ago
11

A bar magnet cut in half will form a total ofpoles.a)fourb)eightc)two​

Physics
1 answer:
Temka [501]3 years ago
8 0

Answer:

A bar magnet is exactly 2 poles, if you cut it in half, you would have 4 poles.

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Calculate the final speed of a 110-kg rugby player who is initially running at 8.00 m/s but collides head-on with a padded goalp
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<span>The answer is -0.8 m/s. We know acceleration is the average of final minus initial velocity over time (a = (vf-v0)/t). We also know that Force is equal to Mass times Acceleration (F = ma). Using our force equation, we know that the acceleration we get is negative 8.8 (-8.8). The force is acting in the opposite direction of the rugby player, hence the negative sign. From there, plug in that number for a in the velocity equation, and solve for vf, as v0 and t are known. We get 0.8 m/s in the opposite direction that the player was running.</span>
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2 years ago
A force is applied to an object at rest with a mass of 100 kg. A force twice as large is applied to another object at rest with
MAVERICK [17]
The second object, the one that had twice the force applied to it, would move twice as far, I believe.
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2 years ago
Which condition is required for Coulomb's law to hold true?
AleksAgata [21]
The correct answer is:
<span>Point charges must be in a vacuum.

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<span>where
</span>\epsilon_0 is the permittivity of free space
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q is the separation between the two charges

However, this formula is valid only if the charges are in vacuum. If they are in a material medium, the law is modified as follows:
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7 0
2 years ago
A positively charged particle initially at rest on the ground accelerated upward to 100m/s in 2.00s. If the particle has a charg
VashaNatasha [74]

Answer:

Explanation:

From the question we are told that

     The initial velocity is  u  =  100 m/s

       The time taken is  t = 2.0 s

       The charge to mass ratio is  Q/m  =  0.100 C/kg

       

Generally the acceleration is mathematically evaluated as

              a  =   \frac{u}{t }

substituting values  

               a =   \frac{100}{2}

                a =  50 \ m/s^2

The electric field is mathematical represented as

             E = \frac{(a+g)}{Q/m}

substituting values

              E = \frac{(50+9.8)}{0.100}

              E = 598 \ N/C

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2 years ago
A machine has an efficiency of 20%. Find the input work if the output work is 140J.
Ilia_Sergeevich [38]
Ummmm I don’t know this sorry
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