2x-8/x^2 what is the range of this function ?

1 answer:

5 0

The function is continuous for $x>0$ . It goes to $-\infty$ when $x\to0$ and it goes to $+\infty$ when $x\to+\infty$ hence its range is $\Bbb{R}=(-\infty,+\infty)$

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How do you solve a-9/a3

Klio2033 [76]

Is it this?
$\frac{a - 9}{a3}$
If so, then
$\frac{a - 9}{a3} = 0 \\ \frac{a}{a3} - \frac{9}{a3} = 0 \\ \frac{1}{3} - \frac{9}{a3} \\ \frac{1}{3} = \frac{9}{a3} \\ 3( \frac{1}{3} ) = 3( \frac{9}{a3} ) \\ 1 = \frac{9}{a} \\ a = 9$

5 0

3 years ago

HELP ME PLEASE AND THANKS

gavmur [86]

X is equal to 22.25 so all you have to do is to fill it in and find the answers

8 0

3 years ago

Margie is standing on a bridge looking at the river below. She throws a rock over the bridge with an initial

Marina CMI [18]

<h2>Explanation:</h2><h2></h2>

Here we know that Margie is standing on a bridge looking at the river. She throws a rock over the bridge with an initial velocity of 60 ft/sec. The height, h, of the rock at the rime t seconds after it was thrown can be modeled by the equation:

$h(t) = -16t^2+60t+72$

To calculate how long will it take for the rock to reach the surface of the water, we need to set $h(t)=0$ . So:

$0 = -16t^2+60t+72 \\ \\ \\ \text{Using quadratic formula}: \\ \\ t=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ \\ a=-16 \\ \\ b=60 \\ \\ c=72 \\ \\ \\ t=\frac{-60 \pm \sqrt{60^2-4(-16)(72)}}{2(-16)} \\ \\ t=\frac{-60 \pm \sqrt{60^2-4(-16)(72)}}{2(-16)} \\ \\ t=\frac{-60 \pm \sqrt{8208}}{-32} \\ \\ t_{1}=4.70 \\ \\ t_{2}=-0.95$

Given that time can't be negative, we just choose the positive value. Therefore, <em>it will take 4.70 seconds for the rock to reach the surface water.</em>

6 0

3 years ago

If you add my number to it's self and add 83 you will get the same number as when you add my number 4 times and subtract 25

Deffense [45]

I think you should put in 53 try that

7 0

3 years ago

What is the cost of constructing a fence 6 feet, 6 inches, high around a lot measuring 90 feet by 175 feet, if the cost of erect

lions [1.4K]

Answer:

The total cost is $3504.625

Step-by-step explanation: