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3 years ago

2x-8/x^2 what is the range of this function ?

1 answer:

5 0

The function is continuous for $x>0$ . It goes to $-\infty$ when $x\to0$ and it goes to $+\infty$ when $x\to+\infty$ hence its range is $\Bbb{R}=(-\infty,+\infty)$

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The stem-and-leaf plot shows test scores for students in Math 7. How many students earned more than a 65 on their test? Key 4|5

Nadya [2.5K]

the answer is b

Step-by-step explanation:

hope this helps if not let me know have a blessed day

7 0

2 years ago

Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th

Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

(a)

The bid should be greater than $10,000 to get accepted by the seller. Let bid x be a continuous random variable that is uniformly distributed between

$10,000 and $15,000

The interval of the accepted bidding is $[ {\rm{\$ 10,000 , \$ 15,000}]$ , where b = $15000 and a = $10000.

The interval of the provided bidding is [$10,000,$12,000]. The probability is calculated as,

$\begin{array}{c}\\P\left( {X{\rm{ < 12,000}}} \right){\rm{ = }}1 - P\left( {X > 12000} \right)\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{12000}^{15000}\\\end{array}$

$=1- \frac{[15000-12000]}{5000}\\\\=1-0.6\\\\=0.4$

(b) The interval of the accepted bidding is [$10,000,$15,000], where b = $15,000 and a =$10,000. The interval of the given bidding is [$10,000,$14,000].

$\begin{array}{c}\\P\left( {X{\rm{ < 14,000}}} \right){\rm{ = }}1 - P\left( {X > 14000} \right)\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{14000}^{15000}\\\end{array} P(X14000)$

$=1- \frac{[15000-14000]}{5000}\\\\=1-0.2\\\\=0.8$

(c)

The amount that the customer bid to maximize the probability that the customer is getting the property is calculated as,

The interval of the accepted bidding is [$10,000,$15,000],

where b = $15,000 and a = $10,000. The interval of the given bidding is [$10,000,$15,000].

$\begin{array}{c}\\f\left( {X = {\rm{15,000}}} \right){\rm{ = }}\frac{{{\rm{15000}} - {\rm{10000}}}}{{{\rm{15000}} - {\rm{10000}}}}\\\\{\rm{ = }}\frac{{{\rm{5000}}}}{{{\rm{5000}}}}\\\\{\rm{ = 1}}\\\end{array}$

(d) The amount that the customer bid to maximize the probability that the customer is getting the property is $15,000, set by the seller. Another customer is willing to buy the property at $16,000.The bidding less than $16,000 getting considered as the minimum amount to get the property is $10,000.

The bidding amount less than $16,000 considered by the customers as the minimum amount to get the property is $10,000, and greater than $16,000 will depend on how useful the property is for the customer.

5 0

3 years ago

Cos^3a-sin^3a/cosa-sina

KIM [24]

Answer:

1 + cosa sina

Step-by-step explanation:

$\frac{cos^3a-sin^3a}{cosa-sina}$

cos³a - sin³a ← is a difference of cubes and factors in general as

a³ - b³ = (a - b)(a² + ab + b²) , then

cos³a - sin³a

= (cosa - sina )(cos²a + cosa sina + sin²a)

= (cosa - sina)(1 + cosa sina) [ sin²a + cos²a = 1 ]

Then

$\frac{cos^3a-sin^3a}{cosa-sina}$

= $\frac{(cosa-sina)(1+cosasina)}{cosa-sina}$ ← cancel (cosa - sina) on numerator/ denominator

= 1 + cosa sina

8 0

2 years ago

Samuel orders four DVDs from an online music store. Each DVD costs $9.67. He has a 25% discount code,

ra1l [238]

Answer:9999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999[

99999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999

Step-by-step explanation:[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[

[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[[88888888888888888888888888888888888888

5 0

2 years ago

Determine the volume of a cylinder if its height is 5mm and a radius of 12mm

Elenna [48]

Answer:

Step-by-step explanation:

V = pi * r^2 * h

r = 12 mm

h = 5 mm

pi = 3.14

V= 3.14 * 12^2 * 5

V = 3.14 * 144 * 5

V = 2260.8 cm^3

3 0

3 years ago