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laila [671]
3 years ago
13

2x-8/x^2 what is the range of this function ?

Mathematics
1 answer:
lapo4ka [179]3 years ago
5 0
The function is continuous for x>0. It goes to -\infty when x\to0 and it goes to +\infty when x\to+\infty hence its range is \Bbb{R}=(-\infty,+\infty)
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