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Korolek [52]
3 years ago
12

Ivan biked 1 whole 2/3 on Monday, 2 wholes 1/3 hours on Tuesday, and 2 wholes 2/3 on Wednesday. What is the total number of hour

s Ivan spent biking?
Mathematics
1 answer:
GenaCL600 [577]3 years ago
5 0
1 \frac{2}{3} + 2 \frac{1}{3} + 2 \frac{2}{3} =

\frac{3*1+2}{3} +  \frac{3*2+1}{3} +  \frac{3*2+2}{3} =

\frac{3+2}{3} +  \frac{6+1}{3} +  \frac{6+2}{3} =

\frac{5}{3} + \frac{7}{3} + \frac{8}{3} =

=  \frac{20}{3} h

In hours:

20 |_3
(2)....6hs
x60' 
------
120' |_3
(0)....40' 

Answer:
<span>6hs40min

</span>or<span>

</span>\frac{20}{3} hs =  \frac{20}{3} *60' =  \frac{1200}{3} = 400'
<span>
400' = 6*60' = 360' + 40' = 400' (True)
</span>Until

<span>6hs40min</span>
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What is the value of the variable -38 = 2b + 25 - (-7b)
ddd [48]
The variable in this equation is b, therefore we have to calculate the value of b.

-38=2b+25-(-7b)
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We can check it out this answer:
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3 years ago
Any volunteer please help
den301095 [7]

Answer:

Part A)

The equation in the point-slope form is:

y-11=\frac{4}{3}\left(x-\left(-2\right)\right)

Part B)

The graph of the equation is attached below.

Step-by-step explanation:

Part A)

Given

  • The point = (-2, 11)
  • m = 4/3

The point-slope form of the line equation is

y-y_1=m\left(x-x_1\right)

Here, m is the slope and (x₁, y₁) is the point

substituting the values m = 4/3 and the point (-2, 11)  in the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

y-11=\frac{4}{3}\left(x-\left(-2\right)\right)

Thus, the equation in the point-slope form is:

y-11=\frac{4}{3}\left(x-\left(-2\right)\right)

Part B)

As we have determined the point-slope form which passes through the point (-2, 11) and has a slope m = 4/3

The graph of the equation is attached below.

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3 years ago
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Answer:

Step-by-step explanation:

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