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Lostsunrise [7]
3 years ago
6

How many unique ways are there to arrange the letters in the word DEN?

Mathematics
2 answers:
nata0808 [166]3 years ago
8 0

the answer would be 6 NOT 2

Tatiana [17]3 years ago
5 0
2 is the correct answer I'm almost definite
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C-5=10 ans plz......
Umnica [9.8K]

Answer:

c = 5

Step-by-step explanation:

c - 5 = 10 \\ c = 10 + 5 \\ c = 15

<h3>Hope it is helpful....</h3>
6 0
2 years ago
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David drives 168 miles a week he fill his tank 2 times a week each fill up is 12 gallons what is gas mileage on his car
Umnica [9.8K]
I think it would be 7 miles per gallon. Just do Miles/Gallons per week.


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3 years ago
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A rental car company charges $31 per day to rent a car and $0.13 for every mile
lord [1]

Answer:

The number of days is at most 5 days

= d ≤ 5 days

Step-by-step explanation:

A rental car company charges $31 per day to rent a car and $0.13 for every mile driven. Jocelyn wants to rent a car, knowing that:

She plans to drive 500 miles.

• She has at most $220 to spend.

At most means Less than or equal to $220

The inequality for expressing this = ≤

Hence, the inequality which can be used to determine d, the number of days Jocelyn can afford to rent while staying within her budget.

$31 × d + $0.13 × 500 miles ≤ $200

The inequality is given as:

31d + 65 ≤ 220

Solving further

31d ≤ 220 -65

31d ≤ 155

d ≤ 155/31

d ≤ 5

Therefore, the number of days is at most 5 days

8 0
3 years ago
Please help me find this.​
VMariaS [17]

Answer:

Square I think

Step-by-step explanation:

4 0
2 years ago
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Find the area each sector. Do Not round. Part 1. NO LINKS!!<br><br>​
sladkih [1.3K]

Answer:

\textsf{Area of a sector (angle in degrees)}=\dfrac{\theta}{360 \textdegree}\pi r^2

\textsf{Area of a sector (angle in radians)}=\dfrac12r^2\theta

17)  Given:

  • \theta = 240°
  • r = 16 ft

\textsf{Area of a sector}=\dfrac{240}{360}\pi \cdot 16^2=\dfrac{512}{3}\pi \textsf{ ft}^2

19)  Given:

  • \theta=\dfrac{3 \pi}{2}
  • r = 14 cm

\textsf{Area of a sector}=\dfrac12\cdot14^2 \cdot \dfrac{3\pi}{2}=147 \pi \textsf{ cm}^2

21)  Given:

  • \theta=\dfrac{ \pi}{2}
  • r = 10 mi

\textsf{Area of a sector}=\dfrac12\cdot10^2 \cdot \dfrac{\pi}{2}=25 \pi \textsf{ mi}^2

23)  Given:

  • \theta = 60°
  • r = 7 km

\textsf{Area of a sector}=\dfrac{60}{360}\pi \cdot 7^2=\dfrac{49}{6}\pi \textsf{ km}^2

3 0
2 years ago
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