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Sever21 [200]
3 years ago
6

O eliminate the y-terms and solve for x in the fewest steps, by which constants should the equations be multiplied? First Equati

on: 5x − 4y = 28 Second equation: 3x - 9y = 30
A.The first equation should be multiplied by 3 and the second equation by 5.B.The first equation should be multiplied by 3 and the second equation by −5.C.The first equation should be multiplied by 9 and the second equation by 4.D.The first equation should be multiplied by 9 and the second equation by −4.
Mathematics
1 answer:
IceJOKER [234]3 years ago
7 0
"<span>D.The first equation should be multiplied by 9 and the second equation by −4." makes sense.  Let's do this work:

</span><span>First Equation: 5x − 4y = 28 Second equation: 3x - 9y = 30

45x - 36y = 252
-12x+36y = -120
----------------------
33 x = 132, so x = 4.  And so on.</span>
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IF THE RATIO OF TYPE O TO NON-TYPE O DONOR AT THE
Amiraneli [1.4K]

Answer:

139 donors

Step-by-step explanation:

So we have 37:43 as ratio. Lets add 37 and 43, giving us 80. So let's make the proportion, 37/80 = d/300. (d since d it stands for donors). Now let's cross multiply. 80d = 11100

d=11100/80

d=138.75

u dont just have part of a person, as that is manslaughter, you round to 139

6 0
3 years ago
Find the value of<br>a.) lim (x²-1)/(x²+1)<br>x−&gt;∞<br>​
Fed [463]

Answer:

\displaystyle\lim_{x \to \infty} \frac{x^2-1}{x^2+1} \\ \text{take $x^2$ common from numerator and denominator} \\ \displaystyle\lim_{x \to \infty} \dfrac{1-\frac{1}{x^2}}{1+\frac{1}{x^2}} \\\text{Now put the limit}\\\displaystyle\lim_{x \to \infty} \frac{1-0}{1+0}= 1

6 0
3 years ago
The graph of f(x) = x6 – 2x4 – 5x2 + 6 is shown below.
Andrej [43]

Answer:

Two rational roots: 1 and -1

Step-by-step explanation:

See the images for an explanation!

5 0
3 years ago
Hem dibuixat tres rectangles. En el primer, la llargada mesura 3 cm més que l'amplada. El segon i tercer rectangle tenen unes di
quester [9]

Resposta:

Primer rectangle:

Amplada = 11

Longitud = 14

Segon rectangle:

Amplada = 12

Longitud = 15

Tercer rectangle:

Amplada = 13

Longitud = 16

Explicació pas a pas:

Donat que:

Primer rectangle:

Amplada = x

Longitud = x + 3

2n rectangle:

Augment de la dimensió d'1 cm respecte al primer rectangle;

Amplada = x + 1

Longitud = x + 4

3r rectangle:

Augment de la dimensió de 2 cm respecte al primer rectangle;

Amplada = x + 2

Longitud = x + 5

Suma dels tres perímetres del rectangle:

Perímetre d'un rectangle: 2 (l + O)

Primer rectangle:

2 (x + x + 3) = 2 (2x + 3) = 4x + 6

2n:

2 (x + 1 + x + 4) = 2 (2x + 5) = 4x + 10

3r:

2 (x + 2 + x + 5) = 2 (2x + 7) = 4x + 14

Suma de perímetres = 162

(4x + 6 + 4x + 10 + 4x + 14) = 162

12x + 30 = 162

12x = 162 - 30

12x = 130

x = 11

Per tant,

Primer rectangle:

Amplada = 11

Longitud = 11 + 3 = 14

2n rectangle:

Amplada = 11 + 1 = 12

Longitud = 11 + 4 = 15

3r rectangle:

Amplada = 11 + 2 = 13

Longitud = 11 + 5 = 16

8 0
3 years ago
I need help with number 9 please
Temka [501]
16 160 1600 in order ...........................................
5 0
3 years ago
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