The minimum initial deposit Arthur must make is $ 4.24.
Since Arthur is saving money to buy a used car in 8 months, and the car costs $ 2,180, and Arthur plans to start with an initial deposit and then deposit 25% more than the previous month until he has enough money to buy the car, to determine what is the minimum initial deposit Arthur must make the following calculation should be performed:
- X x 1.25 x 1.56 x 1.95 x 2.44 x 3.05 x 3.81 x 4.76 = 2180
- 514.10X = 2180
- X = 2180 / 514.10
- X = 4.24
Therefore, the minimum initial deposit Arthur must make is $ 4.24.
Learn more about maths in brainly.com/question/25749130
Answer:
3217.00
Step-by-step explanation:
V=πr^2h=π·8^2·16≈3216.99088
Answer:
73
Step-by-step explanation:
Use the PEMDAS method. Start off with exponents, which is 3x3, which equals 9. Then do multiplication, because it comes before addition. So you multiply 9 by 8 to get 72. Then it says +1 so 72+1 equals 73. (Final Answer)
Answer:
12-5, 7-10, 8-5,
Step-by-step explanation:
These three are in simplest form
a. Any vector in the span of
is a linear combination of the vectors in
. The simplest one we could come up with is the addition of the two vectors we know:
![p(x)=(-8x^2+4x-5)+(-2x+5)=\boxed{-8x^2+2x}](https://tex.z-dn.net/?f=p%28x%29%3D%28-8x%5E2%2B4x-5%29%2B%28-2x%2B5%29%3D%5Cboxed%7B-8x%5E2%2B2x%7D)
b. Since one vector is quadratic while the other is purely linear, there is no choice of
such that
![c_1(-8x^2+4x-5)+c_2(-2x+5)=\boxed{x}](https://tex.z-dn.net/?f=c_1%28-8x%5E2%2B4x-5%29%2Bc_2%28-2x%2B5%29%3D%5Cboxed%7Bx%7D)
because the only way to eliminate the
term is to pick
, but there's no way to eliminate the remaining constant term.