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xz_007 [3.2K]
4 years ago
15

Fractions! Simplify. -1 6/7 - (-2 1/7)

Mathematics
1 answer:
swat324 years ago
3 0
-60 or -600

because the answer it gives me is -.5714285714 so if you simplify it should be -.60 or -.600 just depends on the answers you have to pick from. 

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What is an equation of the line that passes through the points (4,-6) and has a slope of -3
lions [1.4K]

Answer:

Step-by-step explanation:

point slope form

y + 6 = -3(x - 4)

point slope to y-intercept

y + 6 = -3x + 12

y = -3x + 6

3 0
3 years ago
Help please I’ll mark you brainliest
prohojiy [21]
Subtract any number from the next one.
-1 - (-6)
4 - (-1)
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All of the above subtractions give the same answer.
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3 0
4 years ago
Let f(x) be a continuous function such that f(1) = 3 and f '(x) = sqrt( x^3 + 4 ). What is the value of f(5)?
snow_lady [41]

The value of f(5) is 49.1

Step-by-step explanation:

To find f(x) from f'(x) use the integration

f(x) = ∫ f'(x)

1. Find The integration of f'(x) with the constant term

2. Substitute x by 1 and f(x) by π to find the constant term

3. Write the differential function f(x) and substitute x by 5 to find f(5)

∵ f'(x) =  + 6

- Change the root to fraction power

∵  =

∴ f'(x) =  + 6

∴ f(x) = ∫  + 6

- In integration add the power by 1 and divide the coefficient by the

 new power and insert x with the constant term

∴ f(x) =  + 6x + c

- c is the constant of integration

∵

∴ f(x) =   + 6x + c

- To find c substitute x by 1 and f(x) by π

∴ π =   + 6(1) + c

∴ π =  + 6 + c

∴ π = 6.4 + c

- Subtract 6.4 from both sides

∴ c = - 3.2584

∴ f(x) =   + 6x - 3.2584

To find f(5) Substitute x by 5

∵ x = 5

∴ f(5) =   + 6(5) - 3.2584

∴ f(5) = 49.1

7 0
3 years ago
Mr. Walker gave his class the function f(x) = (x + 3)(x + 5). Four students made a claim about the function. Each student’s clai
damaskus [11]

Answer: stephen was correct

Step-by-step explanation:

i just did it now

7 0
3 years ago
What can 8 and 32 both divided by​
julia-pushkina [17]

Answer:

2,4,8

Step-by-step explanation:

4 0
3 years ago
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