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3 years ago

Ibuki factored 12 xZ as (4x) (3x4)

Mathematics

1 answer:

user100 [1]3 years ago

8 0

Answer:

Melody

Step-by-step

I guess that it is : $12x^2$

So, when we look at Ibuki, when multiply, ,we got $48x^2$

When we multiply 2x and 6x, which did Melody, we got our result.

So, we can say that Melody factored correctly..

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Find an order pair (x,y) that is a solution to the equation <br> X-4y=4

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(0,-1)

You can guess and check to see what gives you the answer

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A rectangle’s base is 6 cm longer than its height. The rectangle’s area is 135 cm2. Find this rectangle’s dimensions. You must i

il63 [147K]

Area of a rectangle = length x height

Area = 135

Height = X

Lenght = x +6

135 = x * x+6

Simplify:

135 = x^2 +6x

Subtract 135 from both sides:

x^2 + 6x - 135 = 0

Solve:

2 numbers when added need to equal 6 and when multiplied equal -135

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What is y=7/4x+6 if the input was 53

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3 years ago

A population has the following characteristics. (a) A total of 75% of the population survives the first year. Of that 75%, 25% s

Artemon [7]

Answer:

$= \left[\begin{array}{ccc}1344\\84\\28\end{array}\right] \left \begin{array}{ccc}{0 \ \leq age \leq 1 }\\{ 1 \ \leq age \leq 2 }\\{2 \ \leq age \leq 3}\end{array}\right$

i.e after the first year ;

there 1344 members in the first age class

84 members for the second age class; and

28 members for the third age class

Step-by-step explanation:

We can deduce that the age distribution vector x represents the number of population members for each age class; Given that in each class of age there are 112 members present.

The current age distribution vector is as follows:

$x = \left[\begin{array}{ccc}1&1&2\\1&1&2\\1&1&2\end{array}\right] \left[\begin{array}{ccc}{0 \ \leq age \leq 1 }\\{ 0 \ \leq age \leq 2 }\\{0 \ \leq age \leq 3}\end{array}\right]$

Also , the age transition matrix is as follows:

$L = \left[\begin{array}{ccc}3&6&3\\0.75&0&0 \\0&0.25&0\end{array}\right]$

After 1 year ; the age distribution vector will be :

$x_2 =Lx_1 = \left[\begin{array}{ccc}3&6&3\\0.75&0&0 \\0&0.25&0\end{array}\right] \left[\begin{array}{ccc}1&1&2\\1&1&2\\1&1&2\end{array}\right]$

$= \left[\begin{array}{ccc}1344\\84\\28\end{array}\right] \left \begin{array}{ccc}{0 \ \leq age \leq 1 }\\{ 1 \ \leq age \leq 2 }\\{2 \ \leq age \leq 3}\end{array}\right$

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