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siniylev [52]
3 years ago
11

a square garden with a side of 150m has a square swimming pool in the very center with a side length of 25m calculate the area o

f the garden ​

Mathematics
1 answer:
marta [7]3 years ago
7 0

Answer: 21,875 sqm

Step-by-step explanation:

Step 1:

   Find the gross area of the garden.

   Square 150m = 22,500 sqm.

Step 2:

   Find the area of the pool.

   Square 25m = 625 sqm.

Step 3:

   Subtract the area of the pool from the gross area of the garden

   to find the net area of the garden.

   22,500 - 625 = 21,875 sqm.

Warning:

   Do not subtract the side length of the swimming pool from the side length

   of the garden before squaring.

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IRISSAK [1]

Answer:

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Step-by-step explanation:

5 to the fourth power *since you timesed 5x5 four*4* times

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3 years ago
The volume of a sphere can be determined by the formula V = 4/3 πr^3, where r is the radius. What is the volume of a sphere with
allochka39001 [22]

Answer:

V = \frac{99}{7} x^{9}y^{-6}

Step-by-step explanation:

Given

V = \frac{4}{3}\pi r^3

Required

Find V when

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Substitute \frac{3}{2}x^3y^{-2 for r in V = \frac{4}{3}\pi r^3

V = \frac{4}{3}\pi * (\frac{3}{2}x^3y^{-2})^3

Open bracket

V = \frac{4}{3}\pi * \frac{3}{2}^3 * x^{3*3}y^{-2*3}

V = \frac{4}{3}\pi * \frac{27}{8} * x^{9}y^{-6}

Simplify the fractions

V = \pi * \frac{9}{2} * x^{9}y^{-6}

Let

\pi = \frac{22}{7}

So:

V = \frac{22}{7}  * \frac{9}{2} * x^{9}y^{-6}

V = \frac{11}{7} * \frac{9}{1} * x^{9}y^{-6}

V = \frac{99}{7}   * x^{9}y^{-6}

V = \frac{99}{7} x^{9}y^{-6}

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3 years ago
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6 0
2 years ago
Lee is thinking of two Numbers,the product is 18. the quotient is 2
defon
X, y - the numbers

The product is 18.
xy=18

The quotient is 2.
\frac{x}{y}=2 \ \ \ |\times y \\
x=2y

Substitute 2y for x in the 1st equation:
2y \times y=18 \\
2y^2=18 \ \ \ |\div 2 \\
y^2=9 \\
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x=2y \\
x=2 \times 3 \ \lor \ x=2 \times (-3) \\
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6 0
2 years ago
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Find the surface area of the composite solid.
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Answer:

281 ft^2

Step-by-step explanation:

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4 0
2 years ago
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