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3 years ago

ms.johnson gives 1/6 of 1 pizza to each of her 25 students how many pizzas does ms.johnson give her students

2 answers:

6 0

I think it'd be...

25 students each get 1/6 a pizza
- 25/6
-6*4 = 20
-five are left over, so we would put that on top of the 6
Therefore, 4 5/6 (four and five-sixths) would be ur answer.

romanna [79]3 years ago

3 0

Each kid gets 1 slice out of six. so, we have to divide 25 by six, which is 4 r1, which means that one student will get the entire pie to him/herself. (Lucky Duck) and so Ms. Johnson gives her students 5 pizza. Hope this helps!

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Ok I have a question it says, " Ella can read 2 pages in 3 minutes. How long will it take her to read 45 pages?". So I just don'

Vaselesa [24]

Answer:

67.5

Step-by-step explanation:

this gives you the basis of the problem, 2 pages every 3 minutes, so that means that you have to divide 45 by 2, this will give you 22.5

then you multiply by 3 because 22.5 is how many sets of 2 Ella has to read, and if we remember every set of 2 pages takes 3 minutes, so 22.5 times 3 is 67.5, but if you want the answer in time it would be 67 minutes and 30 seconds because a minute is 60 seconds and half of that is 30

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3 years ago

When 60% of a number is added to the number, the result is 192. What is the number? Show your work.

Natali [406]

Let the original number be
x

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7 0

3 years ago

Plz help me with this

Marrrta [24]

Answer: c) 3

<u>Step-by-step explanation:</u>

Plug in y = -9 and the given x-value to see if it makes a true statement.

a) -4.5 falls in the piecewise function x < -3 --> y = -x

y = -x

-9 = -(-4.5)

-9 = 4.5 FALSE

b) -3 falls in the piecewise function -3 ≤ x ≤ -2 --> y = 2x

y = 2x

-9 = 2(-3)

-9 = -6 FALSE

c) 3 falls in the piecewise function x > -2 --> y = -x²

y = -x²

-9 = -(-3)²

-9 = -9 TRUE

d) 9 falls in the piecewise function x > -2 --> y = -x²

y = -x²

-9 = -(9)²

-9 = -81 FALSE

4 0

3 years ago

Please solve the problem with steps

Debora [2.8K]

Answer:

Infinite series equals 4/5

Step-by-step explanation:

Notice that the series can be written as a combination of two geometric series, that can be found independently:

$\frac{3^{n-1}-1}{6^{n-1}} =\frac{3^{n-1}}{6^{n-1}} -\frac{1}{6^{n-1}} =(\frac{1}{2})^{n-1} -\frac{1}{6^{n-1}}$

The first one: $(\frac{1}{2})^{n-1}$ is a geometric sequence of first term ( $a_1$ ) "1" and common ratio (r) " $\frac{1}{2}$ ", so since the common ratio is smaller than one, we can find an answer for the infinite addition of its terms, given by: $Infinite\,Sum=\frac{a_1}{1-r} = \frac{1}{1-\frac{1}{2} } =\frac{1}{\frac{1}{2} } =2$

The second one: $\frac{1}{6^{n-1}}$ is a geometric sequence of first term "1", and common ratio (r) " $\frac{1}{6}$ ". Again, since the common ratio is smaller than one, we can find its infinite sum:

$Infinite\,Sum=\frac{a_1}{1-r} = \frac{1}{1-\frac{1}{6} } =\frac{1}{\frac{5}{6} } =\frac{6}{5}$

now we simply combine the results making sure we do the indicated difference: Infinite total sum= $2-\frac{6}{5} =\frac{10-6}{5} =\frac{4}{5}$

8 0

3 years ago

Read 2 more answers

I need the answer for this exact question

denis23 [38]

Answer:

$y=\frac{7}{2}x-20$

Step-by-step explanation:

Let the equation of the line be $y-y_1=m(x-x_1)$ where, 'm' is its slope and $(x_1,y_1)$ is a point on it.

Given:

The equation of a known line is:

$y=-\frac{2}{7}x+9$

A point on the unknown line is:

$(x_1,y_1)=(4,-6)$

Both the lines are perpendicular to each other.

Now, the slope of the known line is given by the coefficient of 'x'. Therefore, the slope of the known line is $m_1=-\frac{2}{7}$

When two lines are perpendicular, the product of their slopes is equal to -1.

Therefore,

$m\cdot m_1=-1\\m=-\frac{1}{m_1}\\m=-\frac{1}{\frac{-2}{7} }=\frac{7}{2}$

Therefore, the equation of the unknown line is determined by plugging in all the given values. This gives,

$y-(-6))=\frac{7}{2}(x-4)\\y+6=\frac{7}{2}x-14\\y=\frac{7}{2}x-14-6\\\\y=\frac{7}{2}x-20$

The equation of a line perpendicular to the given line and passing through (4, -6) is $y=\frac{7}{2}x-20$ .

3 0

3 years ago