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saul85 [17]
2 years ago
15

How can you write a fraction as a decimal?

Mathematics
1 answer:
Sedbober [7]2 years ago
3 0
You take the numerator and divide that by the denominator
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What do we do to both sides of this equation to solve?
anzhelika [568]

Add 10 to both sides

Step-by-step explanation:

x-10 = 8

x - 10 + 10 = 8+ 10

x = 18

8 0
2 years ago
Read 2 more answers
What is 65.5 percent as a decimal
adell [148]

<u>Answer:</u>

65.5/100 = 0.665

<u />

<u>Step-by-step explanation:</u>

*Hope this helps*

4 0
2 years ago
An operations analyst counted the number of arrivals per minute at an ATM in each of 30 randomly chosen minutes. The results wer
liraira [26]

Step-by-step explanation:

since Poisson distribution parameter is not given so we have to estimate it from the sample data. The average number of of arrivals per minute at an ATM is

\hat{\lambda}=\bar{x}=\frac{\sum x}{n}=\frac{30}{30}=1

So probabaility for \mathrm{X}=1 is

P(X=1)=\frac{e^{-\lambda} \lambda^{x}}{x !}=\frac{e^{-1} \cdot 1^{1}}{1 !}=0.3679

So expected frequency for X=1 is 0.3679^{*} 30=11.037 (or \left.11.04\right) .

8 0
3 years ago
There are 3 boxes for green chips and 5 boxes for red chips. each box has the same number of chips in it. if there are a total o
Sauron [17]

Answer:

<h2>2 in each box of course</h2>

g= green chips       r= red chips

3 boxes of green chips meaning for each box there are <em>2</em> chips so there are 6 green chips. 5 boxes of red chips meaning for each box there are two chips so there are 10 red chips and 6 g + 10r = 16 chips in total

Step-by-step explanation:

6 0
2 years ago
the numbers 2-12 are written on cards and placed in the bag.what is the probability of picking an even number then replacing it
lorasvet [3.4K]

We have the cards numbered as 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, and 12.

Sample number is, n(S)=11.

We pick a card and want to get even number like 2, 4, 6, 8, 10, and 12.

Probability of picking an even number would be :-

P(even numbers) = \frac{6}{11}

Now we replace the card and want to get a 7 in second attempt.

Probability of picking a 7 would be :-

P(number 7) = \frac{1}{11}

Now Probability of this event = P(even numbers) × P(number 7)

Probability = (\frac{6}{11} )(\frac{1}{11} ) = \frac{6}{121}

So final answer is \frac{6}{121}.

3 0
3 years ago
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