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3 years ago

I will give brainliest if i can too

Mathematics

1 answer:

weeeeeb [17]3 years ago

6 0

Answer:

164 respondents answered "yes"

69 respondents answered "yes"

126 respondents answered "yes"

Step-by-step explanation:

Let's take these problems one at a time.

First problem: 195 Juniors and 215 Seniors. 2 out of 5 answered "yes".

Now let's first find the total number of students.

Total Students = 195 + 215

Total Students = 410

Now 2 out of 5 also means the 2/5 or 40% of the students answered yes.

To see how many said yes, we simple multiply the total number of students to the value of 40% or 0.40.

Total Students that answered "yes" = 410 x 0.40

Total Students that answered "yes" = 164

Second Problem: 125 Juniors and 220 Seniors. 0.80 answered "no".

Same process, we first look for the total number of students.

Total Students = 125 + 220

Total Students = 345

Now 0.80 or 80% of them said "no".

We take the total number of students and multiply the number of students to the value of 80% or 0.80.

Total Students that answered "no" = 345 x 0.80

Total Students that answered "no" = 276

Now to find out how many answered "yes", we subtract the total number of students to the students that said "no".

Total Students that answered "yes" = 345 - 276

Total Students that answered "yes" = 69

Third Problem 200 Juniors and 160 Seniors. 35% answered "yes"

Same process, we first look for the total number of students.

Total Students = 200 + 160

Total Students = 360

To see how many said yes, we simple multiply the total number of students to the value of 35% or 0.35.

Total Students that answered "yes" = 360 x 0.35

Total Students that answered "yes" = 126

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Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

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3 years ago

suppose you have three consecutive integers. The greatest of the three integers is twice as great as the sum of the first two. W

zvonat [6]

Answer:

0,1,2

Step-by-step explanation:

(x+2) = 2((x+1)+(x)

x+2 = 2x+2+2x

x+2 = 4x+2

-x -x

2 = 3x + 2

-2 -2

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3 years ago

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dybincka [34]

AnsweR = 50
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