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Sindrei [870]
3 years ago
7

Find the greatest common factor of 4w and 6c^3

Mathematics
2 answers:
Natali5045456 [20]3 years ago
5 0

Answer:

Step-by-step explanation:

The Greatest Common Factor (GCF) of the numbers

f 4w and 6c^3

is

1

because 1 is the greatest number that divides evenly into all of them.

faust18 [17]3 years ago
4 0

Answer: The greatest common factor of 4 and 6 is 2

Step-by-step explanation:

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Choose a variable to represent one of the unknowns. Express the remaining unknowns in terms of the variable you chose in step 1.
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Let's just choose "x" as our variable for the length of a side of the triangle.

Two sides of a triangle are equal in length and double the length of the shortest side.

A triangle has 3 sides. Make the smallest side x then the two equal sides that are double the smallest side are both equal to 2x

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Step-by-step explanation:

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3 years ago
According to the National Vital Statistics, full-term babies' birth weights are Normally distributed with a mean of 7.5 pounds a
Sav [38]

Answer:

68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 7.5, \sigma = 1.1

What is the probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

This is the pvalue of Z when X = 8.6 subtracted by the pvalue of Z when X = 6.4. So

X = 8.6

Z = \frac{X - \mu}{\sigma}

Z = \frac{8.6 - 7.5}{1.1}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 6.4

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.4 - 7.5}{1.1}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

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3 years ago
When a person agrees to a regular, fixed payment of wages over a period of time, he/she agrees to earn a
navik [9.2K]
I’m pretty sure it’s wage or salary
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3 years ago
Read 2 more answers
Consider a circle whose equation is x2 + y2 + 4x – 6y – 36 = 0. Which statements are true? Check all that apply. To begin conver
umka21 [38]

Answer:

1) False, to begin converting the equation to standard form, each side must be added by 36. 2) True, to complete the square for the x terms, add 4 to both sides, 3) True, the center of the circle is at (-2, 3), 4) False, the center of the circle is at (-2, 3), 5) False, the radius of the circle is 7 units, 6) False, the radius of the circle is 7 units.

Step-by-step explanation:

Let prove the validity of each choice:

1) To begin converting the equation to standard form, subtract 36 from both sides:

Let consider the following formula and perform the following algebraic operations:

(i) x^{2} + y^{2} + 4\cdot x - 6\cdot y  - 36 = 0 Given

(ii) x^{2} + 4\cdot x + y^{2} - 6\cdot y - 36 = 0 Commutative Property

(iii) (x^{2} + 4\cdot x + 4) - 4 + (y^{2} - 6\cdot y + 9) - 9 -36 = 0 Modulative/Associative Property/Additive Inverse Existence

(iv) (x+ 2)^{2} - 4 + (y - 3)^{2} - 9 - 36 = 0  Perfect Trinomial Square

(v) (x+2)^{2} +(y-3)^{2} = 4 + 9 + 36 Commutative Property/Compatibility with Addition/Additive Inverse Existence/Modulative Property

(vi) (x+2)^{2} + (y-3)^{2} = 49 Definition of Addition/Result

False, to begin converting the equation to standard form, each side must be added by 36.

2) True, step (iii) on exercise 1) indicates that both side must be added by 4.

3) The general equation for a circle centered at (h, k) is of the form:

(x-h)^{2}+ (y-k)^{2} = r^{2}

Where r is the radius of the circle.

By direct comparison, it is evident that circle is centered at (-2,3).

True, step (vi) on exercise 1) indicates that center of the circle is at (-2, 3).

4) False, step (vi) on exercise 1) indicates that the center of the circle is at (-2, 3), not in (4, -6).

5) After comparing both formulas, it is evident that radius of the circle is 7 units.

False, the radius of the circle is 7 units.

6) After comparing both formulas, it is evident that radius of the circle is 7 units.

False, the radius of the circle is 7 units.

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3 years ago
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