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trapecia [35]
2 years ago
7

Bert already has $50 but needs a total of at least $250 for his holiday. He gets paid $20 per day for delivering papers. What is

the least number of days he must work to get enough money for his holiday?
Mathematics
1 answer:
aleksley [76]2 years ago
4 0

Answer:

Bret would need to work for 8 days.

Step-by-step explanation:

He has $50 and needs to pay $250. 250-50= 200. £20 is $27.59 200/27.59 =7.24 If £20 is a typo then 10 days.

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Help me i need it to pass
Harrizon [31]

The answer is 8.

8x4=32

(8x7)-(8x3)=32

Hope this helps!

5 0
2 years ago
PLZ
kirza4 [7]

see below

Step-by-step explanation:

2.) $230 x 28% = $64.40

$230 - $64.40 = $165.60 sales price

3.) $45,000 × 25% = $11,250

$45,000 - $11,250 = $33, 750 discount price

$45,000 + $11,250 = $56,250 mark up price

$56,250 - $33,750 = $22,500 answer

4.) $33,750 x 8.875% = $2995.31

$33,750 + $2995.31 = $36,745.31 with tax

5.) $56,250 x 8.875% = $4,992.19

$56,250 + $4,992.19 = $61,242.19 with tax

6.) $33,750 x 6% = $2,025.00 Tom's commision

8 0
3 years ago
Read 2 more answers
How to put the answer in a mixed number? (35^3/8)
motikmotik
Write the decimal number as a fraction
(over 1)
35.375 = 35.375 / 1

Multiplying by 1 to eliminate 3 decimal places
we multiply top and bottom by 3 10's
<span>= 35  3/8</span>
5 0
3 years ago
What is the expression for the below sequence (use n)<br><br> -3,-6,-9,-12
polet [3.4K]

Answer:

a_{n} = - 3n

Step-by-step explanation:

There is a common difference between consecutive terms, that is

- 6 - (- 3) = - 9 - (- 6) = - 12 - (- 9) = - 3

This indicate the sequence is arithmetic with n th term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 3 and d = - 3 , thus

a_{n} = - 3 - 3(n - 1) = - 3 - 3n + 3 = - 3n

The n th term is - 3n

6 0
3 years ago
Find the distance between points P(8, 2) and Q(3, 8) to the nearest tenth.
riadik2000 [5.3K]
<span>First of all to calculate the distance between two points we can use distance formula
   
d=Square Root [(x2-x1)^2 + (y2-y1)^2]
   
Now substitute the given points p(x1,y1) and q(x2,y2)in above distance formula
   
The values are X2=3, X1=8and Y2=8and Y1=2.
   
After Substituting the values
   
d=Square Root[(-5)^2+(6)^2]
   
d=Square Root(25+36]
   
d=Square Root[61]
   
d=7.8
   
7.8 is the distance between points P(8, 2) and Q(3, 8) to the nearest tenth.</span>
7 0
3 years ago
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