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Paha777 [63]
3 years ago
13

The function f(x) = –2(x – 10)(x – 200) represents a company's monthly profit as a function of the number of items sold, x. What

is the maximum monthly profit?
Mathematics
2 answers:
stepladder [879]3 years ago
7 0

what you do first is you times the F which will equal -2 which will give you an answer then you subtract that answer by 10 * by 200 than you have your answer

Thepotemich [5.8K]3 years ago
3 0

Answer:

The maximum monthly profit is 18050.

Step-by-step explanation:

The given function is

f(x)=-2(x-10)(x-200)

f(x)=(-2x+20)(x-200)

f(x)=-2x(x-200)+20(x-200)

f(x)=-2x^2+400x+20x-4000

f(x)=-2x^2+420x-4000              .... (1)

The vertex of a quadratic function  

g(x)=ax^2+bx+c          ..... (2)

is defend as

(\frac{-b}{2a},f(\frac{-b}{2a}))

From (1) and (2) we get

a=-2,b=420,c=-4000

\frac{-b}{2a}=\frac{-420}{2(-2)}=105

Put x=105 in the given function.

f(105)=-2(105-10)(105-200)

f(105)=-2(95)(-95)

f(105)=18050

Therefore the maximum monthly profit is 18050.

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