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Nataly [62]
2 years ago
5

It is estimated that 28.5% of automobile crashes are caused by driver distraction, such as texting. If there are 16,370 automobi

le crashes in a study, what number would be caused by driver distractions?
Mathematics
1 answer:
frez [133]2 years ago
6 0

Answer:

4665 approx

Step-by-step explanation:

Given data

Total number of crashes=  16,370 automobile crashes

Percentage caused by distraction =28.5%

Let us find the number of crashes caused by distraction

=28.5/100* 16,370

=0.285* 16,370

=4665.45

Hence the number of crashes caused by distraction is 4665 approx

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Step-by-step explanation:

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2 years ago
If JKLM is a rhombus, MK = 30, NL = 13, and mZMKL = 41°, find each measure.
oksian1 [2.3K]

Answer:

NK = 15

JL = 26

KL = 19.85

\angle JKM =49

\angle JML =41

\angle MLK = 90

\angle MNL =90

\angle KJL =41

Step-by-step explanation:

Given

MK = 30

NL = 13

\angle MKL = 41

Solving (a): NK

MK is a diagonal and NK is half of the diagonal. So:

NK = \frac{1}{2} * MK

NK = \frac{1}{2} * 30

NK = 15

Solving (b): JL

JL is a diagonal, and it is twice of NL.

JL = 2 * NL

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Solving (c): KL

To solve for KL, we consider triangle KNL where:

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and

KL^2 = NL^2 + NK^2

KL^2 = 13^2 + 15^2

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KL = \sqrt{394

KL = 19.85

Solving (d - h):

To do this, we consider triangle JKN

\angle KNL = \angle LNM = \angle MNJ = \angle JNK = 90 -- diagonals bisect one another at right angle

Alternate interior angles are equal. So:

\angle MKL = \angle KMJ = \angle KJL = \angle JLM = 41

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\angle MKJ = \angle KML = \angle MJL = \angle JLK = 90 - 41

\angle MKJ = \angle KML = \angle MJL = \angle JLK = 49

So:

\angle JKM =49

\angle JML =41

\angle MLK = \angle MLJ + \angle JLK

\angle MLK = 49 + 41

\angle MLK = 90

\angle MNL =90

\angle KJL =41

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