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3 years ago

I need a answer please

Mathematics

1 answer:

mel-nik [20]3 years ago

8 0

Answer:

-1.75 and .75 i believe

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Geralds baby brother spends 7/8 ofhis day sleeping. How many hours does his baby brother sleep

Effectus [21]

His baby brother sleeps 21 hours.
There's a total of 24 hours in a day so you can divide by 8. That means 1/8 of the day is equal to 3 hours, so 7 times 3 hours equals 21 hours

6 0

3 years ago

Write the standard equation of a circle that passes through (−2, 10) with center (−2, 6).

Liono4ka [1.6K]

Standard form of a circle" (x-h)²+(y-k)²=r², (h,k) being the center, r being the radius.
in this case, h=-2, k=6, (x+2)²+(y-6)²=r²
use the point (-2,10) to find r: (-2+2)²+(10-6)²=r², r=4
so the equation of the circle is: (x+2)²+(y-6)²=4²

6 0

3 years ago

Read 2 more answers

You make a dessert with lemon gelatin and lime gelatin. What percent of the dessert is lime-flavored? Explain

pentagon [3]

Answer:

i struggle with this to sry and hey

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

The line L passes through the points (0, –2) and (6, 1).<br><br> Find an equation of the line L.

lesya692 [45]

Answer:

Some Facts about lines (1) For non vertical line L, if L passes a point (x0,y0) with slope m, then an equation of line L is y − y0 = m(x − x0). (2) If a non vertical line L passes through distinct points (x1,y1) and x2(y2), then the slope of L is m = y2 − y1 x2 − x1 . x a + y b = 1.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Use Newton's Method to approximate the zero(s) of the function. Continue the iterations until two successive approximations diff

liubo4ka [24]

Answer:

There is only one real zero and it is located at x = 1.359

Step-by-step explanation:

After the 4th iteration the solution was repeating the first 3 decimal places. The formula for Newton's Method is

$x_{n}-\frac{f(x_{n}) }{f'(x_{n}) }$

If our function is

$f(x)=x^5+x-6$

then the first derivative is

$f'(x)=5x^4+1$

I graphed this on my calculator to see where the zero(s) looked like they might be, and saw there was only one real one, somewhere between 1 and 2. I started with my first guess being x = 1.

When I plugged in a 1 for x, I got a zero of 5/3.

Plugging in 5/3 and completing the process again gave me 997/687

Plugging in 997/687 and completing the process again gave me 1.36976

Plugging in 1.36976 and completing the process again gave me 1.359454

Plugging in 1.359454 and completing the process again gave me 1.359304

Since we are looking for accuracy to 3 decimal places, there was no need to go further.

Checking the zeros on the calculator graphing program gave me a zero of 1.3593041 which is exactly the same as my 5th iteration!

Newton's Method is absolutely amazing!!!

5 0

3 years ago