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nika2105 [10]
3 years ago
13

Which recursive formula can be used to determine the total amount of money earned for each successive hour worked based on the a

mount of money currently earned
Mathematics
1 answer:
sveticcg [70]3 years ago
5 0

Complete question is;

An electrician earns $110 after his first hour of working for a client. His total pay based on the number of hours worked can be represented using the sequence shown.

110, 130, 150, 170, ...

Which recursive formula can be used to determine the total amount of money earned for each successive hour worked based on the amount of money currently earned?

Answer:

The recursive formula can be expressed as; f(x + 1) = f(x) + 20

Step-by-step explanation:

Electrician earns $110 dollars after working for 1 hour.

We were told his total pay based on number of hours worked can be represented by: 110, 130, 150, 170...

This means that writing it down as a function, we can say;

f(1) = $110, f(2) = $130 e.t.c

Now,since we want to express a recursive formula to explain the question, then let's say after the 1 hour worked, he earned $110, then the hour after that, his total is $130,then the hour after that, his total is $150.

This means that he earns an additional $20 each hour.

Thus;

f(x + 1) = f(x) + 20

Where x is number of hours and f(x) is payment after x number of hours

The recursive formula can be expressed as; f(x + 1) = f(x) + 20

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Answer:

x=0

y=6

Step-by-step explanation:

3y- 12x = 18

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2y-8x=12

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2y=8x+12

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Recheck:

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4 years ago
As part of a screening process, computer chips must be operated in an oven at 145 °C. Ten minutes after starting, the temperatur
Novosadov [1.4K]

Answer:

Step-by-step explanation:

I solved this using initial conditions and calculus, so I hope that's what you are doing in math.  It's actually NOT calculus, just a concept that is taught in calculus.

The initial condition formula we need is

y=Ce^{kt}

Filling in our formula with the 2 conditions we are given:

65=Ce^{10k}   and   85=Ce^{15k}

With those 2 equations, we have 2 unknowns, the C (initial value) and the k (the constant). We know that the initial value (or starting temp) for both conditions is the same, so we solve for C in one equation, sub it into the other equation and solve for k.  If

65=Ce^{10k} then

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C=65e^{-10k}

Since that value of C is the same as the value of C in the other equation, we sub it in:

85=65e^{-10k}(e^{15k})

Divide both sides by 65 and use the rules of exponents again to get

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Do the log thing on your calculator to get

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k = .0536527973

Now that we have k, we sub THAT value in to one of the original equations to find C:

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65=Ce^{.536527973}

Raise e to that power on your calculator to get

65 = C(1.710059171) and divide to solve for C:

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Now sub in k and C to the final problem when t = 23:

y=38.01038064e^{(.0536527973)(23)} which simplifies a bit to

y=38.01038064e^{1.234014338}

Raise e to that power on your calculator to get

y = 38.01038064(3.434991111) and

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130.565

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