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nika2105 [10]
3 years ago
13

Which recursive formula can be used to determine the total amount of money earned for each successive hour worked based on the a

mount of money currently earned
Mathematics
1 answer:
sveticcg [70]3 years ago
5 0

Complete question is;

An electrician earns $110 after his first hour of working for a client. His total pay based on the number of hours worked can be represented using the sequence shown.

110, 130, 150, 170, ...

Which recursive formula can be used to determine the total amount of money earned for each successive hour worked based on the amount of money currently earned?

Answer:

The recursive formula can be expressed as; f(x + 1) = f(x) + 20

Step-by-step explanation:

Electrician earns $110 dollars after working for 1 hour.

We were told his total pay based on number of hours worked can be represented by: 110, 130, 150, 170...

This means that writing it down as a function, we can say;

f(1) = $110, f(2) = $130 e.t.c

Now,since we want to express a recursive formula to explain the question, then let's say after the 1 hour worked, he earned $110, then the hour after that, his total is $130,then the hour after that, his total is $150.

This means that he earns an additional $20 each hour.

Thus;

f(x + 1) = f(x) + 20

Where x is number of hours and f(x) is payment after x number of hours

The recursive formula can be expressed as; f(x + 1) = f(x) + 20

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Maggie incorrectly says that the percent of mute swans is equivalent to 536. Explain her likely error.
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Which is the measure of angle C ?
zubka84 [21]

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A

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if the triangles are similar the ange B and E are the same, A and D are the same and C and F are the same.

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8 0
3 years ago
If limx→3f(x)=7, which of the following must be true? I. f is continuous at x = 3 II. f is differentiable at x = 3
Viktor [21]

Without knowing anything else about f(x), neither of these need be true.

Suppose

f(x)=|x-3|+7=\begin{cases}10-x&\text{for }x3\\0&\text{for }x=3\end{cases}

Then (I) isn't true because, while the limit exists as x\to3 and is equal to 7, we have f(3)=0\neq7, so f(x) is not continuous there.

(II) also true because f(x) is not differentiable at x=3; that is,

\displaystyle\lim_{x\to3^-}f'(x)=\lim_{x\to3}(10-x)'=\lim_{x\to3}(-1)=-1

but

\displaystyle\lim_{x\to3^+}f'(x)=\lim_{x\to3}(x+4)'=\lim_{x\to3}1=1

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3 0
3 years ago
What is the solution?
Ilia_Sergeevich [38]

Answer:

A. {3+7i,3-7i}

Step-by-step explanation:

The given equation  is  x^2-6x+58=0

Use the quadratic formula with a=1,b=-6 and c=58

Recall the quadratic formula;

x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

We substitute the given values to get;

x=\frac{--6\pm \sqrt{(-6)^2-4(1)(58)} }{2(1)}

x=\frac{6\pm \sqrt{36-232} }{2}

x=\frac{6\pm \sqrt{-196} }{2}

Recall that;

\sqrt{-1}=i

x=\frac{6\pm 14i}{2}

x=3\pm 7i

x=3+7i or x=3-7i

8 0
3 years ago
Read 2 more answers
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