12 because triangles will always have an odd number, and 12 is even
I think
(1.3X10^6ft/hr)(2.8X10^3hr)
(1.3*2.8)(10^6*10^3)
Rule (a^b)(a^c)=a^(b+c)
(3.64)(10^(6+3))
3.64(10^9)
3.64X10^9 ft
Technically we only had two significant figures and the answer should be:
3.6X10^9 if we were to express our answer to the correct number of significant figures....
let's firstly convert the mixed fractions to improper fractions, and then add them up.
![\bf \stackrel{mixed}{8\frac{1}{2}}\implies \cfrac{8\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{17}{2}}~\hfill \stackrel{mixed}{7\frac{2}{3}}\implies \cfrac{7\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{23}{3}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{17}{2}+\cfrac{23}{3}\implies \stackrel{\textit{using the LCD of 6}}{\cfrac{(3)17~~+~~(2)23}{6}}\implies \cfrac{51+46}{6}\implies \cfrac{97}{6}\implies 16\frac{1}{6}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B8%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B8%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B17%7D%7B2%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B7%5Cfrac%7B2%7D%7B3%7D%7D%5Cimplies%20%5Ccfrac%7B7%5Ccdot%203%2B2%7D%7B3%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B23%7D%7B3%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B17%7D%7B2%7D%2B%5Ccfrac%7B23%7D%7B3%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Busing%20the%20LCD%20of%206%7D%7D%7B%5Ccfrac%7B%283%2917~~%2B~~%282%2923%7D%7B6%7D%7D%5Cimplies%20%5Ccfrac%7B51%2B46%7D%7B6%7D%5Cimplies%20%5Ccfrac%7B97%7D%7B6%7D%5Cimplies%2016%5Cfrac%7B1%7D%7B6%7D)