Answer:
I dont know
Step-by-step explanation:
(5,4) simply substitute the values in! they work :) hope it helped
Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900
There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20
The price of an advance ticket was 20.
The price of a same-day ticket was 15.
To answer this question, we will use the sine law which is illustrated in the attached image.
We are given that:The distance from school to library = a
∠A = 32
∠B = 110
b = 2.2
Substitute with the givens in the relation of the sine law to get a as follows:(sin 32) / (a) = (sin 110) / (2.2)
a = (2.2 sin 32) / (sin 110)
distance from school to library = a = 1.2406 mi
Based on the above calculations, the best choice would be:B. 1.2 mi
Answer:
(11⋅7q^6)
Step-by-step explanation:
STEP 1:
11q^6 • 7
STEP 2:
Final result :
(11•7q6)