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FrozenT [24]
3 years ago
9

Guysss I need help ASAPPPP I need to get this done todayyy :(((

Mathematics
2 answers:
PIT_PIT [208]3 years ago
4 0

Answer:

see below

Step-by-step explanation:

t = 7m

Let  m = 6

t = 7*6 = 42

Let m = 8

t = 7*8

t = 56

solniwko [45]3 years ago
4 0

Answer:

For this, all you have to do is multiply each number on the left by 7.

T = 7m

M= 6 x 7

T = 42

M = 8 x 7

T = 56.

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Step-by-step explanation:

The mean is all the numbers added up, divided by how many numbers there are. To get the median you arrange the numbers biggest to smallest and find the middle number.

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In the figure, a ll e, m ll n, and m 3 = 112 degrees <br><br> What is the m 1 ?
Readme [11.4K]

Answer:

∠1 = 112°

Step-by-step explanation:

∠2 = ∠3 = 112° ( corresponding angles )

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3 years ago
Please help me! 15 points
arsen [322]

Answer:

a. The length of FA is 1.

b. The length of the radius (AC) is 2.

c. The circumference of the circle A is 4π units.

d. The measure of the minor arc BC is 107°.

e. The length of the minor arc BC is (107/90) π.

f. The m<BFC and m<EFD is 125.5°.

g. The m<BFE is 180°.


Step-by-step explanation:

Radius: R=AB=2

FC=1

Arc CD = 180°

Minor arc BD = 73°

Minor arc EC = 36°


a. What is the length of FA?

FA=AC-FC

AC is a radius, then AC=AB→AC=2

Replacing in the known values in the equation above:

FA=2-1

FA=1


b. What is the length of the radius (AC)?

The radius AC must be equal to the radius AB, then:

AC=AB→AC=2


c. What is the circumference of the circle A?

Circunference of circle A: L=?

L=2 π R

L=2 π (2)

L=4π


d. What is the measure of the minor arc BC?

Minor arc BC = arc CD - Minor arc BD

Minor arc BC = 180°-73°

Minor arc BC = 107°


e. What is the length of the minor arc BC?

Length of minor arc BC: l=?

l=(Minor arc BC / 360°) L

l=(107°/360°) 4π

l=(4*107/360) π

l=(107/90) π


f.  What is the m<BFC and m<EFD

<BFC and <EFD are interior angles, then:

m<BFC = m<EFD = ( Minor arc BC + Minor arc DE) / 2

Minor arc DE = arc CD - Minor arc EC

Minor arc DE = 180°-36°

Minor arc DE = 144°

m<BFC = m<EFD = ( 107° + 144° ) / 2

m<BFC = m<EFD = ( 251° ) / 2

m<BFC = m<EFD = 125.5°


g. What is the m<BFE?

<BFE is a straight angle, then m<BFE=180°





8 0
3 years ago
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