When we use arcsine, we are finding the angle while giving the trigonometric ratio.
Arcsin(u) = theta can be rewritten as:
sin(theta) = u
Sine is opposite over hypotenuse, so u/1 means that the side opposite to theta (the y value) is u, and the hypotenuse is 1.
We can use Pythagorean Theorem to find the adjacent (x value).
1^2 - u^2 = x^2
x = sqrt(1-u^2)
Back to the original question, we are trying to find cos(arcsin(u)). We just solved all the sides for our triangle using arcsin(u). Now we need to do cos(u).
Cosine is adjacent over hypotenuse.
So our answer is sqrt(1-u^2)/1
Or just sqrt(1-u^2)
Answer:
(0,0), (1,1), (2,2)
Step-by-step explanation:
When testing to find possible points in situations like this, I always start by testing with the origin point (0,0).
In this case:
4x+6y<24 ==> 0 + 0 < 24 TRUE, it satisfies the inequality.
We then try with (1,1):
4x+6y<24 ==> 4 + 6 < 24 TRUE, it satisfies the inequality.
And with (2,2):
4x+6y<24 ==> 8 + 12 < 24 TRUE, it satisfies the inequality.
Answer:
x = 7, y = 30 and x = 3, y = 10
Step-by-step explanation:
5x - y = 5, then y = 5x - 5
2y - x^2 = 11
2(5x - 5) - x^2 = 11
10x - 10 - x^2 = 11
-x^2 + 10x -10 = 11
-x^2 + 10x -21 = 0
x^2 - 10x + 21 = 0
(x - 7)(x - 3) = 0
x = 7, y = 30
x = 3, y = 10
Answer:
Step-by-step explanation:
5out
I mean yeah I'd like to befriends but isn't this a studying app?
