To simplify, we need to find a number that can divide both the numerator and denominator equally. Can you find a number that will do this? I can't. So it is already simplified.
The probability of this question is 1/2
There are 5 even numbers from 1 to 10.
The number of ways to draw all even numbers is 5!/(2!*3!) = 10
The number of ways to draw from the hat is 10!/(7!*3!) = 128
Therefore the probability is 10/128 = 5/64 or roughly 7.81%
