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3 years ago

This is accounting plz help

Mathematics

1 answer:

Margarita [4]3 years ago

4 0

Yh i think that simon may be gay? Do you think? Maybe-

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Which relation is a function

Natali [406]

Answer:

Look at image posted.

Step-by-step explanation:

The one I circle would be the answer because there should not be 2 points for every x-axis value. The 1st one has 2 points with x=0, the other 2 also have 2 points on the asme x axis value

7 0

3 years ago

A level maths factor theorem <br>help in part (b) please

Rina8888 [55]

Given polynomial $f(x)=4 x^{3}-12 x^{2}+2 x-6$ .

(a) To show that (x – 3) is a factor of f(x).

Factor theorem:

<em>A polynomial f(x) has a factor of (x – a), if and only if f(a) = 0.</em>

$f(x)=4 x^{3}-12 x^{2}+2 x-6$

$f(3)=4 (3)^{3}-12 (3)^{2}+2 (3)-6$

$=4(27)-12(9)+6-6$

$=108-108$

= 0

f(3) = 0

Hence (x – 3) is a factor of f(x).

(b) $f(x)=0$

$4 x^{3}-12 x^{2}+2 x-6=0$

Here $4x^2$ is common in first 2 terms and 2 is common in next 2 terms.

$4x^2(x-3 )+2 (x-3)=0$

Now, (x – 3) is common in both terms.

$(x-3)(4x^2+2)=0$

$(x-3)=0$ and $(4x^2+2)=0$

x = 3 and $4x^2+2=0$

3 is the real root.

using quadratic formula solve $4x^2+2=0$ and find the other roots.

$$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

$$x=\frac{-0 \pm \sqrt{0^{2}-4 (4) (2)}}{2 (4)}$

$$x=\pm\frac{\sqrt{-32}}{8}$

$$x=\pm\frac{4\sqrt{2}i}{8}$

$$x=\pm\frac{\sqrt{2}i}{2}$

These are complex roots.

Hence 3 is the only real root of the equation f(x) = 0.

8 0

4 years ago

Read 2 more answers

Which graph represents the function f(x)=0.5^x+4?

inn [45]

f(x)=7 i think this is right please tell mee

4 0

3 years ago

Read 2 more answers

Pencil cost 9p each.how much would 28 pencil cost

Akimi4 [234]

Answer:

Step-by-step explanation:

9 times 3 is 28

5 0

4 years ago

Read 2 more answers

Consider the function.

matrenka [14]

The correct options are:

a) g(x) = 8*x - 6

b) g(x) = 2x - 10

c) g(x) = 2x - 14

d) g(x) = 8x - 24

<h3>How to identify each transformation?</h3>

Here we have the function:

f(x) = 2x - 6

The proposed transformations are:

a) Stretch by a factor of 4 along the x-axis.

A horizontal stretch of scale factor k is written as:

g(x) = f(x*k).

Then, in this case, we have:

g(x) = 2(x*4) - 6 = 8*x - 6

b) Shift f(x) 4 units down.

A vertical shift of N units is written as:

g(x) = f(x) + N

A shift of 4 units down is written as:

g(x) = f(x) - 4 = 2x - 6 - 4 = 2x - 10

c) Shift f(x) 4 units right.

An horizontal shift of N units is written as:

g(x) = f(x + N).

For a shift of 4 units to the right, we write:

g(x) = f(x - 4) = 2(x - 4) - 6 = 2x - 8 - 6 = 2x - 14

d) A vertical compression of scale factor 1/4.

A vertical compression of scale factor K is written as:

g(x) = f(x)/K

In this case, we will have:

g(x) = f(x)/(1/4) = 4*f(x) = 4*(2x - 6) = 8x - 24

If you want to learn more about transformations:

brainly.com/question/4289712

#SPJ1

3 0

2 years ago