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antoniya [11.8K]
4 years ago
9

Horses and zebras can be bred to produce a zorse, which is sterile. Which is most likely the reason zebras and horses are consid

ered separate species?
Biology
1 answer:
Assoli18 [71]4 years ago
6 0
The fact that they can breed but cannot produce fertile offspring shows that they are different species. T<span>hey may have different characteristics which means they cannot breed </span>successfully, too.

I hope this helps! :-)
xo Leafling
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What are human trachea epithelium specialized to do
disa [49]

Answer:

To moisten and to protect the airway from stuff like unknown pathogens and infection

Explanation:

The Trachea also known as the windpipe has tons of 'little hairs' called cilia in the epithelium that protect the throat. When someone smokes or breathes in gases it is destroyed and exposes the trachea. But thats another story. :)

6 0
3 years ago
Выберите верные утверждения:
Lorico [155]

Explanation:

1. У умных птиц у них только очень хорошо развит мозжечок.

U umnykh ptits u nikh tol'ko ochen' khorosho razvit mozzhechok.

2.  Это не правда; В случае самок птиц у нее один яичник, у них единственный - левый (правый атрофируется во время развития вместе с соответствующим яйцеводом), чьи соответствующие протоки открываются в клоаку или в половые отверстия.

V sluchaye samok ptits u neye odin yaichnik, u nikh yedinstvennyy - levyy (pravyy atrofiruyetsya vo vremya razvitiya vmeste s sootvetstvuyushchim yaytsevodom), ch'i sootvetstvuyushchiye protoki otkryvayutsya v kloaku ili v polovyye otverstiya.

3.Так и есть; зародышевый диск медленно растет на поверхности желтка с образованием бластодермы. Часть бластодермы, которая образует органы, является лишь частью бластодиска: zona pellucida; таким образом, инвагинация сводится к этой области в центральной первичной депрессии.

Tak i yest'; zarodyshevyy disk medlenno rastet na poverkhnosti zheltka s obrazovaniyem blastodermy. Chast' blastodermy, kotoraya obrazuyet organy, yavlyayetsya lish' chast'yu blastodiska: zona pellucida; takim obrazom, invaginatsiya svoditsya k etoy oblasti v tsentral'noy pervichnoy depressii.

4. Большинство видов гнездятся на земле, и их гнезда содержат от 4 до 12 яиц, окруженных пухом, сорванным с груди и живота самки. Птенцы плавают и кормятся самостоятельно вскоре после вывода из яйца. Некоторые виды, такие как североамериканская утка, гнездятся в дуплах деревьев и без проблем используют гнезда из искусственной древесины. Их птенцы могут без вреда выпрыгнуть из гнезда и вскоре войти в воду.

Bol'shinstvo vidov gnezdyatsya na zemle, i ikh gnezda soderzhat ot 4 do 12 yaits, okruzhennykh pukhom, sorvannym s grudi i zhivota samki. Ptentsy plavayut i kormyatsya samostoyatel'no vskore posle vyvoda iz yaytsa. Nekotoryye vidy, takiye kak severoamerikanskaya utka, gnezdyatsya v duplakh derev'yev i bez problem ispol'zuyut gnezda iz iskusstvennoy drevesiny. Ikh ptentsy mogut bez vreda vyprygnut' iz gnezda i vskore voyti v vodu.

4 0
3 years ago
Which has a physical property?
stiv31 [10]

Boiling point. If you boil water it changes from a liquid to a gas, which is a physical change. The rest are chemical properties because the chemical make up of an object changes.

8 0
3 years ago
You eat a french fry. As you chew and swallow, some of the particles go down the ‘wrong tube' (the trachea), and this causes you
Stels [109]

Answer:

Your answer is "Cilia".

4 0
3 years ago
Suppose a population is carrying a condition controlled by two alleles: P (dominant) and p (recessive). Only homozygous individu
Virty [35]

<span>The answer is B. 72.25 percent.

The Hardy-Weinberg principle can be used:</span>

<em>p² + 2pq + q² = 1 </em>and <em>p + q = 1</em>

where <em>p</em> and <em>q</em> are the frequencies of the alleles, and <em>p²</em>, <em>q²</em> and <em>2pq</em> are the frequencies of the genotypes.

<span>The <em>p</em> allele (<em>q</em>) is found in 15% of the population:
q = 15% = 15/100
Thus, q = </span><span>0.15

To calculate the <em>P</em> allele frequency (<em>p</em>), the formula <em>p + q = 1</em> can be used:
If p + q = 1, then p = 1 - q
p = 1 - 0.15
Thus, </span><span>p = 0.85

Knowing the frequency of the <em>P</em> allele (<em>p</em>), it is easy to determine the frequency of the <em>PP </em>genotype (<em>p²</em>):
p² = 0.85² = 0.7225

Expressed in percentage, p² = 72.25%.</span>

7 0
3 years ago
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