Answer:
0.4550
Explanation:
In this example, R allele is dominant, so individuals RR and Rr can roll their tongues. If in a population of 1000 gorillas, there are 575 gorillas who can roll their tongues, they will be RR and Rr.
In this case, there is Hardy Weinberg Equilibrium, so the following will be true:
Where:
frequency of RR
frequency of Rr
frequency of rr
The question is what is the frequency of heterozygotes, or, what is the value of 2pq.
We know that RR+Rr is 575 individuals in a population of 1000, or 0.575.
In other words:
So, it is possible to find 
:
Now, there are two alleles in the population, so the following will be true:
It is possible to find q (the frequency of allele r) and p (the frequency of allele p):
Therefore:
Now, the frequency of heterozygotes or 2pq is:
Answer:
One factor would be adaptation to the environment. The brown rabbit blends in and doesn't stand out to predators
The second factor because the white rabbits do stand out to predators they are then killed and can not reproduce.
Explanation:
Answer:
This signifies that the protein primarily comprises multiple polypeptide chains connected together with the help of disulfide bonds. The enzymes may be found in the form of dimers, trimers, or tetramers. Various examples of dimers, trimers, and tetramer proteins are known, of them, NEMOs dimers are considered to be held by disulfide bonds.
Thus, it can be hypothesized that the enzyme under examination is a multimer held in combination by disulfide bonds, with each comprising catalytic sites. On breaking of disulfide bonds, the enzyme dissociates into its many single units.
This illustrates the reduction in catalytic activity. Each active site in a single unit will work, however, at a gradual rate. This also shows detection of multiple globular proteins after disulfide reduction.
B) surface area and temperature
Answer:
yes. a ecosystem consist of both biotic and abiotic factor
