E. One cell contains more mitochondria than the other.
Answer:
Plants are mainly multicellular, of the kind exemplified by trees, shrubs, herbs, grasses, ferns, and mosses, typically growing in a permanent site, absorbing water and inorganic substances through its roots, and synthesizing nutrients in its leaves by photosynthesis using the green pigment chlorophyll.
Explanation:
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<3 <em>Good luck</em>
If the cells stop dividing and do not spread, the tumor is benign
Symbolic interactionists see society as being continually reconstructed by individuals through their use of shared symbols.
<h3>What is symbolic interactionism?</h3>
Symbolic interactionism is a method used to describe human interactions by focusing on the meanings that individuals assign to objects in the world around them such as writings and figures or structures.
Those who study symbolic interactionism are known as symbol interactionists.
Symbol interactionists see human behavior in terms of the symbols which they share.
In conclusion, symbols are part of human society.
Learn more about symbol interactionism at: brainly.com/question/2125966
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Answer:
c. 1:2:1
The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.
Explanation:
If flower color were determined by a gene showing incomplete dominance, the possible genotypes and phenotypes are as follows:
- RR- red
- ww - white
- Rw - pink
If pink sweet peas are self-pollinated, then a cross between two heterozygous individuals is done (Rw x Rw).
<u>From this cross the expected ratios are:</u>
- 1/4 RR (red)
- 2/4 Rw (pink)
- 1/4 ww (white)
So the null hypothesis is that the observed results exhibit a 1:2:1 ratio.
<h3><u>Chi square test</u></h3>

<u>The observed frequencies were:</u>
Total 150
<u>The expected frequencies for our null hypothesis are:</u>
- 1/4 x 150 = 37.5 Red
- 2/4 x 150 = 75 Pink
- 1/4 x 150 = 37.5 white


The degrees of freedom (DF) are calculated as number of phenotypes - 1; in this case DF = 3-1 = 2.
If we look at the Chi square table, for 2 DF and a probability of p0.05, the critical value is 5.991
Our X^2 value of 0.5067 is less than the critical value, so we do not reject the null hypothesis. The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.