All categories

2 years ago

Help me on this Please

Mathematics

1 answer:

Alja [10]2 years ago

6 0

Pythagorean Theorem:
a^2 + b^2 = c^2
Since you have the hypotenuse, you can change the equation to find the missing side.
a^2 - c^2 = - b^2
Insert your numbers:
9^2 - 10^2 = -b^2
What do you get?

You might be interested in

Given x∥y and m∠2=23° .<br><br> What is m∠7?<br><br> Enter your answer in the box.

malfutka [58]

Answer:

angle2=23°

angle7=angle5

angle2=angle6

so,angle8=23°

total angle = 180°

angle7=180°-46°=134°÷2=67°

3 0

2 years ago

ſ x - 5y = -9( 4x + 4y = - 12Step 1 of 2: Determine if the point (-4,1) lies on both of the lines in the system of equations by

Phoenix [80]

Given:

$\begin{gathered} x-5y=-9\ldots\ldots(1) \\ 4x+4y=-12\ldots\text{.}\mathrm{}(2) \end{gathered}$

The given point is (-4,1)

Let's check the ordered pair (-4,1) in the first equation

$\begin{gathered} x-5y=-9 \\ (-4)-5(1)=-9 \\ -4-5=-9 \\ -9=-9 \end{gathered}$

Hence, (-4,1) is a solution of the first equation x-5y=-9.

Now, let's check (-4,1) in the second equation.

$\begin{gathered} 4x+4y=-12 \\ 4(-4)+4(1)=-12 \\ -16+4=-12 \\ -12=-12 \end{gathered}$

So, (-4,1) is a solution of the second equation 4x+4y=-12.

Hence, (-4,1) is a solution of both equation in the system, then it is a solution to the overall system.

3 0

7 months ago

Round 1,129.872 to the nearest hundred

sp2606 [1]

1,129.872 to the nearest hundred is 1,100

3 0

2 years ago

Read 2 more answers

Find the nth term of the sequence 17,21,25,29…

USPshnik [31]

Answer:

Plass 4 every time

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Rewrite the rational exponent as a radical by extending the properties of integer exponents.

Aloiza [94]

$\bf ~~~~~~~~~~~~\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} \qquad \qquad \cfrac{1}{a^n}\implies a^{-n} \qquad \qquad a^n\implies \cfrac{1}{a^{-n}} \\\\\\ \textit{also recall that }a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} \qquad \qquad \sqrt[ m]{a^ n}\implies a^{\frac{ n}{ m}} \\\\ -------------------------------$

$\bf \cfrac{11^{\frac{2}{5}}}{11^{\frac{1}{4}}}\implies 11^{\frac{2}{5}}\cdot 11^{-\frac{1}{4}}\implies 11^{\frac{2}{5}-\frac{1}{4}}\implies 11^{\frac{8-5}{20}}\implies 11^{\frac{3}{20}} \\\\\\ \sqrt[20]{11^3}\implies \sqrt[20]{1331}$

5 0

3 years ago

Read 2 more answers