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kap26 [50]
3 years ago
5

Evaluate when x = -3 and y= -1: A. -4 B. -3 C. 0 D. -6

Mathematics
2 answers:
Zarrin [17]3 years ago
3 0

Answer:

BHNJMKUYJNGTRVFDXWSDFVGYHUJMIKHBGYNUMIYUNTEQWSXEGTHYUJ

Step-by-step explanation:

VHJIMKUBGFCDS

Zolol [24]3 years ago
3 0

Answer:

The anwser is B. -3 Hope This Helps!

Step-by-step explanation:

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Point C is located 8 inches from point A and 6 inches from point B. Points A and B are 2 inches apart.
marshall27 [118]

Answer:

B

Step-by-step explanation:

4 0
2 years ago
How do I solve this problem
Rufina [12.5K]
X+5+2x-2+90=180. combine like terms and solve like a normal algebra problem to find x. if you need to find the answer for a certain angle, plug in the value you got for x into one of the angle equations
8 0
3 years ago
Find the equation whose graph is shown below. Write your answer in standard form.
vladimir2022 [97]

Answer:

it as a liner function that is why we should choose to point in order to find the liner equation

y=2/3x+1

5 0
2 years ago
Sam walks at a rate of 300 ft per minute. How many inches per second does he walk? (1 foot = 12 inches)
bazaltina [42]
300/min
300/60 seconds
300 divided by 60=5
5 ft/second
5ft=60 inches
60 inches/second

Final Answer: B
6 0
3 years ago
How many pairs of consecutive natural numbers have a product of less than 40000? I am in 5th grade. This is supposed to be easy
Ugo [173]

Answer:

There are 199 pairs of consecutive natural numbers whose product is less than 40000.

Step-by-step explanation:

We notice that such statement can be translated into this inequation:

n \cdot (n+1) < 40000

Now we solve this inequation to the highest value of n that satisfy the inequation:

n^{2}+n < 40000

n^{2}+n -40000

The Quadratic Formula shows that roots are:

n_{1,2} = \frac{-1\pm\sqrt{1^{2}-4\cdot (1)\cdot (-40000)}}{2\cdot (1)}

n_{1,2} = -\frac{1}{2}\pm \frac{1}{2} \cdot \sqrt{160001}

n_{1} = -\frac{1}{2}+\frac{1}{2}\cdot \sqrt{160001}

n_{1} \approx 199.501

n_{2} = -\frac{1}{2}-\frac{1}{2}\cdot \sqrt{160001}

n_{2} \approx -200.501

Only the first root is valid source to determine the highest possible value of n, which is n_{max} = 199. Each natural number represents an element itself and each pair represents an element as a function of the lowest consecutive natural number. Hence, there are 199 pairs of consecutive natural numbers whose product is less than 40000.

6 0
3 years ago
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