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Stells [14]
3 years ago
14

PLEASSSSSSSSSSSSSSSE I NEED HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
nikitadnepr [17]3 years ago
4 0
A because x+10x is 11x and 2-4 is -2
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What number divided by 8 equals 9
lora16 [44]

9 x 8= 72, so the answer would be:


72

7 0
3 years ago
Read 2 more answers
The line passing through (-2,5) and (2,p) has a gradient of -1/2. <br><br> Fnd the value of p
makkiz [27]

Given:

The line passing through (-2,5) and (2,p) has a gradient of -\dfrac{1}{2}.

To find:

The value of p.

Solution:

If a line passes through two points, then the slope of the line is:

m=\dfrac{y_2-y_1}{x_2-x_1}

The line passing through (-2,5) and (2,p). So, the slope of the line is:

m=\dfrac{p-5}{2-(-2)}

m=\dfrac{p-5}{2+2}

m=\dfrac{p-5}{4}

It is given that the gradient or slope of the line is -\dfrac{1}{2}.

\dfrac{p-5}{4}=-\dfrac{1}{2}

On cross multiplication, we get

2(p-5)=-4(1)

2p-10=-4

2p=-4+10

2p=6

Divide both sides by 2.

p=3

Therefore, the value of p is 3.

4 0
2 years ago
The number of chocolate chips in an​ 18-ounce bag of chocolate chip cookies is approximately normally distributed with mean 1252
dangina [55]

Answer:

Um I think it is 120%, but i am not totalyy sure

3 0
2 years ago
For the following problem, assume that all given angles are in simplest form, so that if A is in QIV you may assume that 270° &l
d1i1m1o1n [39]

Answer:

Step-by-step explanation:

Given that angle A is in IV quadrant

So A/2 would be in II quadrant.

sin A = -1/3

cos A = \sqrt{1-sin^2 A} =\frac{2\sqrt{2} }{3}

(cos A is positive since in IV quadrant)

Using this we can find cos A/2

cosA = 2cos^2 \frac{A}{2} -1\\Or cos \frac{A}{2} =-\sqrt{\frac{1+cosA}{2} } =-\sqrt{\frac{3+2\sqrt{2} }{6} }

3 0
2 years ago
Cheyenne is playing a board game. Her score was - 130 at the start of her turn, and at the end of her turn
Svet_ta [14]

Answer: -245

Step-by-step explanation: The reason is because if you add -245 to -130 you will get her present score which is -375.

-245 + (-130)

6 0
3 years ago
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