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Ksenya-84 [330]
3 years ago
11

Find the inverse of the function f(x) = 2x – 4.

Mathematics
2 answers:
Vsevolod [243]3 years ago
5 0

The correct answer for this is D) g(x) = 1/2x + 2

Because f(x) is one to one,  its inverse is a function.

irga5000 [103]3 years ago
4 0
Replace <span><span>f<span>(x)</span></span><span>fx</span></span> with <span>yy</span>.<span><span>y=<span><span>2x</span><span>−4</span></span></span><span>y=<span><span>2x</span><span>-4</span></span></span></span>Interchange the variables.<span><span>x=<span><span>2y</span><span>−4</span></span></span><span>x=<span><span>2y</span><span>-4</span></span></span></span>Solve for <span>yy</span>.Tap for more steps...<span><span>y=<span>2+<span>x2</span></span></span><span>y=<span>2+<span>x2</span></span></span></span>Solve for <span>yy</span> and replace with <span><span><span>f<span>−1</span></span><span>(x)</span></span><span><span>f<span>-1</span></span>x</span></span>.
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PLSS HELP ASAP TYSM &lt;33 SORRY I COULDN'T FIND SCIENCE LOLL ​
dimaraw [331]

Answer:

Rock D.

Step-by-step explanation:

We can assume that the force that the catapult does is always the same.

So, here we need to remember Newton's second law:

F = m*a

force equals mass times acceleration.

Where acceleration is the rate of change of the velocity.

So, if we want the rock to hit closer to the catapult, the rock must be less accelerated than rock B.

So, we can rewrite:

a = F/m

So, as larger is the mass of the rock, smaller will be the acceleration of the rock after it leaves the catapult (because the mass is in the denominator). So if we want to have a smaller acceleration, we need to choose a rock with a larger mass than rock B.

Assuming that the mass depends on the size, the only one that has a mass larger than rock B is rock D.

So we can assume that rock D is the correct option.

5 0
3 years ago
What is the equation of the line that is parallel to 8x-5y=2 and goes through the point (-5,-2)
Stella [2.4K]

Answer:

8x - 5y = - 30

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 8x - 5y = 2 into this form

Subtract 8x from both sides

- 5y = - 8x + 2 ( divide all terms by - 5 )

y = \frac{8}{5} x - \frac{2}{5} ← in slope- intercept form

with slope m = \frac{8}{5}

• Parallel lines have equal slopes, hence

y = \frac{8}{5} x + c ← is the partial equation of the parallel line

To find c substitute (- 5, - 2) into the partial equation

- 2 = - 8 + c ⇒ c = - 2 + 8 = 6

y = \frac{8}{5} x + 6 ← in slope- intercept form

Multiply through by 5

5y = 8x + 30 ( subtract 5y from both sides )

0 = 8x - 5y + 30 ( subtract 30 from both sides )

8x - 5y = - 30 ← in standard form

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3 years ago
Who needs help below 8th grade
luda_lava [24]

Answer:

mee

Step-by-step explanation:

7 0
3 years ago
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If you apply ghe change below to the quadratic parent function f(x)=x2 what is the equation of the new function? Shift 1 unit ri
saveliy_v [14]

1 to left gives (x -1)^2

vertical stretch makes it 5(x - 1)^2

reflection in axis changes the sign to - :-

equation of new function is f(x) = -5(x - 1)^2

6 0
3 years ago
The​ _____ _____, denoted ModifyingAbove p with caretp​, is given by the formula ModifyingAbove p with caretpequals=​_____, wher
Vlada [557]

Answer:

The​ <u>sample proportion</u>, denoted by  ^p​, is given by the formula ^p=​ \frac{x}{n}, where x is the number of individuals with a specified characteristic in a sample of n individuals.

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<em>sample mean</em> can be stated as p and <em>sample standard error</em> can be found using the equation\sqrt{\frac{p*(1-p)}{n} } where

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3 years ago
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