i honestly hav no clue good luck
Answer:
It's exactly normal, because both populations are normally distributed.
Step-by-step explanation:
khan :)
Answer:

Step-by-step explanation:
1 .1 ( .1 repeating) = 
Let x=0.1
Then 10x = 1.1111...
= 10 + 0.(1)
= 10+ x.
So, 9x=10 and lastly, x= 
Answer:
After population (A) = 62,902 (Approx)
Step-by-step explanation:
Given:
Current population (P) = 19613
Number of years (n) = 2020 - 2000 = 20 year
Rate of growth (r) = 6% = 0.06
Find:
After population (A)
Computation:
![After\ population (A) = Current\ population (P)[1+r]^n \\\\After\ population (A) = 19613[1+0.06]^{20} \\\\After\ population (A) = 19613[1.06]^{20} \\\\After\ population (A) = 62,901.548](https://tex.z-dn.net/?f=After%5C%20population%20%28A%29%20%3D%20Current%5C%20population%20%28P%29%5B1%2Br%5D%5En%20%5C%5C%5C%5CAfter%5C%20population%20%28A%29%20%3D%2019613%5B1%2B0.06%5D%5E%7B20%7D%20%5C%5C%5C%5CAfter%5C%20population%20%28A%29%20%3D%2019613%5B1.06%5D%5E%7B20%7D%20%5C%5C%5C%5CAfter%5C%20population%20%28A%29%20%3D%2062%2C901.548)
Solve whats in the parentheses first
5k+25+4<21+6k
5k+29<21+6k
plug in a number in k for both sides
5(1)+29<21+6(1)
5+29<21+6
34<27
5(2)+29<21+6(2)
10+29<21+12
39<33
so 5(k+5)+4 is greater than 21+6k