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pishuonlain [190]
3 years ago
5

A sandwich shop offers 4 different meats and 2 different cheeses. Suppose the sandwich shop offers 24 different meat-cheese sand

wiches. How many different breads does the sandwich shop use?
Mathematics
1 answer:
Sergio039 [100]3 years ago
4 0

Answer:

Step-by-step explanation:

You would do this question like this.

4 meats * 2 cheeses * x breads = 24 different kinds of  sandwiches.

8x = 24

8x/8 = 24/8

x = 3

There are 3 different kinds of breads.

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Find the domain and range of the exponential function h(x) = –343x.
Amanda [17]

The function is supposed to be;

h(x) = -343^(x)

Answer:

The domain will be a set of real numbers while the range will be y ≤ 0 and on the interval (-∞, 1)

As x is increasing, h is decreasing and as x is decreasing, h is increasing

Step-by-step explanation:

We are given the function as;

h(x) = -343^(x)

The formula is;

y = a^(x) since it's symmetrical to the x-axis

However in this case;

y = -a^(x)

Now, the domain is y and the range is a set of values of x.

I've attached a graph of this function drawn on desmos.

From the graph we can see that The domain will be a set of real numbers while the range will be on the interval (-∞, 1)

For a value of x = 0,we have;

h(0) = -343^(0)

h(0) = -343

When we increase the value of x to 3,we have;

h(3) = -343^(3)

h(3) = -40353607

When we decrease the value of x to -3, we have;

h(-3) = -343^(-3)

h(-3) = 0.00000002478

Thus, we can conclude that;

As x is increasing, h is decreasing and as x is decreasing, h is increasing

4 0
3 years ago
What kind of sequence is the pattern 1, 6, 7, 13, 20, ...?
AlexFokin [52]

Answer:

The given sequence 6, 7, 13, 20, ... is a recursive sequence

Step-by-step explanation:

As the given sequence is

6, 7, 13, 20, ...

  • It cannot be an arithmetic sequence as the common difference between two consecutive terms in not constant.

As

d = 7-6=1,  d = 13-7=6

As d is not same. Hence, it cannot be an arithmetic sequence.

  • It also cannot be a geometrical sequence and exponential sequence.

It cannot be geometric sequence as the common ratio between two consecutive terms in not constant.

As

r = 7-6=1,  r = 13-7=6

r = \frac{7}{6},  r = \frac{13}{7}

As r is not same, Hence, it cannot be a geometric sequence or exponential sequence. As exponential sequence and geometric sequence are basically the same thing.

So, if we carefully observe, we can determine that:

  • The given sequence 6, 7, 13, 20, ... is a recursive sequence.

Please have a close look that each term is being created by adding the preceding two terms.

For example, the sequence is generated by starting from 1.

     {\displaystyle F_{1}=1

and

     {\displaystyle F_{n}=F_{n-1}+F_{n-2}}

for n > 1.

<em>Keywords: sequence, arithmetic sequence, geometric sequence, exponential sequence</em>

<em>Learn more about sequence from brainly.com/question/10986621</em>

<em>#learnwithBrainly</em>

6 0
3 years ago
Need help with this question ASAP!
kenny6666 [7]

Answer:

(-6, -3)

Step-by-step explanation:

The coordinate is at (2, -1), when using a dilation with a scale factor of 3, multiply the coordinates by 3.

(2, -1) ------> (2 x 3, -1 x 3) ----------> (6, -3)

When reflecting the point over the y-axis, take the opposite of the x coordinate.

(6, -3) ------> (-6, -3)

5 0
2 years ago
PLSSS HELP IF YOU TURLY KNOW THISS
kirill [66]

Answer:

C) 3/4

Step-by-step explanation:

It is three steps out of four.

6 0
2 years ago
Read 2 more answers
Please help ASAP<br><br> If f(x) = x^2-6x+2 and g(x) =sqrt x find a.) (fog) (x)<br> b.) (gof) (-2)
Rudik [331]
\large\begin{array}{l} \left\{\!\begin{array}{l} \mathsf{f(x)=x^2-6x+2}\\ \mathsf{g(x)=\sqrt{x}}\\ \end{array}\right. \end{array}


\large\begin{array}{l} \textsf{a) }\mathsf{(f\circ g)(x)}\\\\ =\mathsf{f\big[g(x)\big]}\\\\ =\mathsf{\big[g(x)\big]^2-6\cdot g(x)+2}\\\\ =\mathsf{\big[\sqrt{x}\big]^2-6\sqrt{x}+2}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(f\circ g)(x)=x-6\sqrt{x}+2} \end{array}}\qquad\checkmark \end{array}

______


\large\begin{array}{l} \textsf{b) }\mathsf{(g\circ f)(-2)}\\\\ =\mathsf{g\big[f(-2)\big]}\\\\ =\mathsf{\sqrt{f(-2)}}\\\\ =\mathsf{\sqrt{(-2)^2-6\cdot (-2)+2}}\\\\ =\mathsf{\sqrt{4+12+2}}\\\\ =\mathsf{\sqrt{18}}\\\\ =\mathsf{\sqrt{3^2\cdot 2}}\\\\ =\mathsf{3\sqrt{2}}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(g\circ f)(-2)=3\sqrt{2}} \end{array}}\qquad\checkmark \end{array}

______


If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2181559


\large\textsf{I hope this helps. :-)}


Tags: <em>composite function composition evaluate algebra</em>

7 0
3 years ago
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