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3 years ago

Please show work, will mark brainliest

Mathematics

1 answer:

Ad libitum [116K]3 years ago

5 0

Answer:

The radius of the can, rounded to the nearest hundredth, is 530.66.

Step-by-step explanation:

We want to do the reverse of the formula for V, which is pi(r)^2(h).

to isolate r.

Let's start by writing an equivalent equation to V = $\pi$ $r^{2}$ h by solving for r

$\sqrt[]{\frac{V * \pi }{h} } = r$

Now, substitute and solve for r

1014 * 3.14 / 6 = 530.66

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Bond [772]

1)
$x^2+8x+16=0 \\
(x+4)^2=0 \\
x+4=0 \\
\boxed{x=-4}$

2)
$x^2-5x-6=0 \\
x^2-6x+x-6=0 \\
x(x-6)+1(x-6)=0 \\
(x+1)(x-6)=0 \\
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x=-1 \ \lor \ x=6 \\
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3)
$\hbox{a perfect square:} \\ (x-a)^2=x^2-2xa+a^2 \\ \\ 2xa=20x \\ a=\frac{20x}{2x} \\ a=10 \\ \\ a^2=10^2=100 \\ \\ \hbox{the expression:} \\ x^2-20x+100 \\ \\ \boxed{\hbox{100 should be added to the expression}}$

4)
$x^2+8x-8=0 \\ \\
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\sqrt{\Delta}=\sqrt{96}=\sqrt{16 \times6}=4\sqrt{6} \\ \\
x=\frac{-b \pm \sqrt{\Delta}}{2a}=\frac{-8 \pm 4\sqrt{6}}{2 \times 1}=\frac{2(-4 \pm 2\sqrt{6})}{2}=-4 \pm 2\sqrt{6} \\
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5)
$2x^2+12x=0 \\
2x(x+6)=0 \\
2x=0 \ \lor \ x+6=0 \\
x=0 \ \lor \ x=-6 \\
\boxed{x=-6 \hbox{ or } x=0}$

6)
$2x^2-2x-1=0 \\ \\
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7)
$x^2-x+2=0 \\ \\
a=1 \\ b=-1 \\ c=2 \\
\Delta=b^2-4ac=(-1)^2-4 \times 1 \times 2=1-8=-7 \\ \\
\boxed{\hbox{the discriminant } \Delta=-7}$

8)
$3x^2-6x+1=0 \\ \\
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\hbox{if } \Delta\ \textless \ 0 \hbox{ then there are no real roots} \\
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9)
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10)
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4 years ago

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noname [10]

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4 years ago

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Ainat [17]

Answer:

Option D, Yes, Devon should have evaluated f(3)

Step-by-step explanation:

f(x) = x^3 + x^2 − 10x + 8

Step 1: Evaluate using F(3) NOT f(-3)

f(3) = 3^3 + 3^2 - 10(3) + 8

f(3) = 27 + 9 - 30 + 8

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Answer: Option D, Yes, Devon should have evaluated f(3)

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4 years ago

Convert this intercept form equation, y=-8.3/100(x+1)(x-5), into standard form, with steps.

Mars2501 [29]

Answer:

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Step-by-step explanation:

Btw brainliest me plss

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3 years ago

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3 years ago

Read 2 more answers