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3 years ago

A 1.8-kg object moves in the x direction according to the following function:

1 answer:

8 0

Well, if the position is <u> x(t) = 2t² + 3t - 5</u>

then the speed is x ' (t) = 4t + 3 (first derivative of 'x' wrt 't')

and the acceleration is x ' ' (t) = 4 (second derivative of 'x' wrt 't')

Apparently, then, the acceleration is constant, and is not a function of time.

After 2.7 seconds or 2.7 years, the acceleration is 4 .

Force = (mass) x (acceleration)

Force = (1.8) x (4)

<em>Force = 7.2 newtons </em>

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Thank you in advance

Musya8 [376]

$m1 = \frac{- v2m2 - m2v1}{v2 - v1}$

8 0

3 years ago

Q2. You push a crate up a ramp with a force of 10 N. Despite your pushing, the crate slides down the ramp 4 m. How much work did

Ksivusya [100]

Answer:

40 J

Explanation:

From the question given above, the following data were obtained:

Force (F) = 10 N

Distance (s) = 4 m

Workdone (Wd) =?

Work done is simply defined as the product of force and distance moved in the direction of the force. Mathematically, we can express the Workdone as:

Workdone = force × distance

Wd = F × s

With the above formula, we can obtain the workdone as follow:

Force (F) = 10 N

Distance (s) = 4 m

Workdone (Wd) =?

Wd = F × s

Wd = 10 × 4

Wd = 40 J

Thus, 40 J of work was done.

5 0

3 years ago

The perceived pitch of a tone is largely determined by its

soldier1979 [14.2K]

The perceived pitch of a tone is largely determined by its frequency

<h3>What is frequency ?</h3>

The frequency of a repeated event is its number of instances per unit of time. In some cases, it is also referred to as temporal frequency or ordinary frequency to underline differences with spatial and angular frequencies, respectively. One (event) per second is equal to one hertz (Hz), which is how frequency is stated.

The period is the reciprocal of the frequency since it is the length of time for one cycle in a repeating occurrence. If a heart beats 120 times per minute (2 hertz), for instance, its period, T—the space between beats—is half a second. In science and engineering, frequency is a crucial metric for describing the temporal rate of change seen in oscillatory systems.

To learn more about frequency from the given link:

brainly.com/question/27216648

#SPJ4

3 0

2 years ago

What is the total current in the circuit? (must include unit - A) REWARD = BRAINLEST

Aleksandr-060686 [28]

Answer:6amperes

Explanation:

1/R=1/40 + 1/40

1/R=2/40

Cross multiplying we get

2R=40

Divide both sides by 2

2R/2 =40/2

R=20ohms

Current=voltage ➗ resistance

Current=120 ➗ 20

Current =6amperes

3 0

3 years ago

Read 2 more answers

A police officer is parked by the side of the road, when a speeding car travelling at 50 mi/hrpasses. The police car immediately

Blababa [14]

Answer:

a) time taken to catch up with speeding car is 12.25 secs

b) the police car will travel 273.8 m to catch up with the speeding car

Explanation:

Given that;

speed of car $V_{c}$ = 50 mi/hr = 22.352 m/s

acceleration of police car = 10 mi/hr = 4.47 m/s²

$V_{f}$ = 70 mi/hr = 31.29 m/s

Now time taken to reach maximum speed is t₁

$V_{f}$ = $V_{i}$ + at₁

we substitute

31.29 = 0 + 4.47t₁

t₁ = 31.29 / 4.47

t₁ = 7 sec

now

d₁ = 0 + 1/2 × at₁²

d₁ = 0 + 1/2 × 0 + 4.47×(7)²

d₁ = 109.5 m

so distance travelled by the speeding car in time t₁ will be

$d_{c}$ = $V_{c}$ × t₁

we substitute

$d_{c}$ = 22.352 × 7

$d_{c}$ = 156.46 m

now distance between polive car and speeding car

Δd = $d_{c}$ - d₁

Δd = 156.46 - 109.5

Δd = 46.96 m

time taken to cover Δd will be

t₂ = Δd / ( $V_{f}$ - $V_{c}$ )

t₂ = 46.96 / ( 31.29 - 22.352 )

t₂ = 46.96 / 8.938

t₂ = 5.25 sec

distance travelled by the police in time t₂ will be

d₂ = $V_{f}$ × t₂

d₂ = 31.29 × 5.25

d₂ = 164.3 m

a) How long will it take before the officer catches up to the speeding car;

time taken to catch up with speeding car;

t = t₁ + t₂

t = 7 + 5.25

t = 12.25 secs

Therefore, time taken to catch up with speeding car is 12.25 secs

b) how far will it have travelled in order to do so;

distance = d₁ + d₂

distance = 109.5 + 164.3

distance = 273.8 m

Therefore, the police car will travel 273.8 m to catch up with the speeding car

6 0

3 years ago