Answer:
3.28 m
3.28 s
Explanation:
We can adopt a system of reference with an axis along the incline, the origin being at the position of the girl and the positive X axis going up slope.
Then we know that the ball is subject to a constant acceleration of 0.25*g (2.45 m/s^2) pointing down slope. Since the acceleration is constant we can use the equation for constant acceleration:
X(t) = X0 + V0 * t + 1/2 * a * t^2
X0 = 0
V0 = 4 m/s
a = -2.45 m/s^2 (because the acceleration is down slope)
Then:
X(t) = 4*t - 1.22*t^2
And the equation for speed is:
V(t) = V0 + a * t
V(t) = 4 - 2.45 * t
If we equate this to zero we can find the moment where it stops and begins rolling down, that will be the highest point:
0 = 4 - 2.45 * t
4 = 2.45 * t
t = 1.63 s
Replacing that time on the position equation:
X(1.63) = 4 * 1.63 - 1.22 * 1.63^2 = 3.28 m
To find the time it will take to return we equate the position equation to zero:
0 = 4 * t - 1.22 * t^2
Since this is a quadratic equation it will have to answers, one will be the moment the ball was released (t = 0), the other will eb the moment when it returns:
0 = t * (4 - 1.22*t)
t1 = 0
0 = 4 - 1.22*t2
1.22 * t2 = 4
t2 = 3.28 s
An object in motion tends to stay in motion an oject at rest stays at rest.
Answer:
Work to move on ion inside a cell = 1.168×10^-20J
Explanation:
Potential difference is a ratio of work done by a charge.
It is given as
◇V= Workdone ×charge= W/a
Workdone = V × q= (7.3×10^-2)×(1.6×10^-19)
W= 1.168×10^-20Joules
Answer:
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Answer:
Time observed by the astronaut = 2.388 hours
Distance traveled be according to an observer on Earth = 1.27 × 10¹¹ m
Distance traveled according to the astronaut = 2.52 × 10¹² m
Explanation:
Given:
Speed of the astronaut, v = 0.980c
time = 12.0 hr
now, from the time dilation formula we have
here
t' is the time observed by the astronaut
c is the speed of the light = 3 × 10⁸ m/s
thus,
or
t' = 2.388 hours
Now,
Distance = Velocity × time
The distance traveled be according to an observer on Earth will be
Distance = 0.980c × ( 12 × 60 × 60 )
or
D = 0.980 × 3 × 10⁸ × ( 12 × 60 × 60 )
or
Distance = 1.27 × 10¹¹ m
And, The distance traveled according to the astronaut will be
Distance = velocity × t'
or
D = 0.980 × 3 × 10⁸ × ( 2.388 × 60 × 60 )
or
Distance = 2.52 × 10¹² m
