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Rom4ik [11]
3 years ago
11

How many miles between a point 60 ° north latitude and 30 ° west longitude and a point 60 ° north latitude and 60 ° east longitu

de?
Physics
2 answers:
kramer3 years ago
7 0

-- We're pretty sure that this question is based on an assumption of EARTH, so we know that we're dealing with a sphere of roughly 3.950 miles radius.

-- The distance on the sphere between 30° west and 60° east is 90° of longitude.  That's 1/4 of the total circumference of the circle.  

-- BUT ..... Way up here at 60° N latitude, the circle is not as big as the equator.  It's radius/diameter/circumference is only cos(60°) = 0.5 of the Earth's total.

-- So the length of our quarter-circle arc is about

(1/4) x (2 · π · 3,950 miles) x (0.5) =

(1/4) x (3,950 π miles) =

988 π miles = 3,104 miles


OlgaM077 [116]3 years ago
3 0

3104 is ur answer I believe

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Glass is transparent to visibile light under normal conditions; however, at extremely high intensities, glass will absorb most o
8_murik_8 [283]

Answer:

3 photons

Explanation:

The energy of a photon E can be calculated using this formula:

E=\frac{hc}{\lambda}

Where h corresponds to Plank constant (6.626070x10^-34Js), c is the speed of light in the vacuum (299792458m/s) and \lambda is the wavelength of the photon(in this case 800nm).

E=\frac{hc}{\lambda}=\frac{(6.626070\times10^{-34})(299792458)}{800\times10^{-9}}=\frac{1.986445812\times10^-25}{800}=2.483057265\times10^{-19}J

Tranform the units

1eV=1.602176634\times10^{-19}J\\2.483057265\times10^{-19}J(\frac{1eV}{1.602176634\times10^{-19}J})=1.549802445eV

The band Gap is 4eV, divide the band gap between the energy of the photon:

\frac{4ev}{1.549802445eV}=2.508974118

Rounding to the next integrer: 3.

Three photons are the minimum to equal or exceed the band gap.

4 0
3 years ago
What is the independent variable of the graph above?
Makovka662 [10]

Answer:

Height of 15 kg Object is the correct answer.

Explanation:

Because the IV (Independent Variable) is always on the x-axis.

6 0
3 years ago
A helicopter has blades of length 4.0 m rotating at 3.0 rev/s in a horizontal plane.If the vertical component of the Earth’s mag
VARVARA [1.3K]

Answer:

Induced emf, \epsilon=9.79\times 10^7\ volts

Explanation:

Given that,

Length of the helicopter, l = 4 m

Angular speed of the helicopter, \omega=3\ rev/s=18.84\ rad/s

The vertical component of the Earth’s magnetic field is, B=6.5\times 10^5\ T

We need to find the induced emf between the tip of a blade and the hub. The induced emf in terms of angular velocity of an rotating object is given by :

\epsilon=\dfrac{1}{2}B\omega l^2

\epsilon=\dfrac{1}{2}\times 6.5\times 10^5\times 18.84\times (4)^2

\epsilon=9.79\times 10^7\ volts

So, the induced emf between the tip of a blade and the hub is \epsilon=9.79\times 10^7\ volts. Hence, this is the required solution.

5 0
3 years ago
You are presently taking a weather observation. The sky is full of wispy cirrus clouds estimated to be about 10 km overhead. If
marshall27 [118]

Answer:

x = 2000 Km

Explanation:

Given

y = 10 km

Slope: 1 : 200

x = ?

We can apply the formula

y / x = 1 / 200   ⇒     x = 200*y = 200*10 Km

⇒     x = 2000 Km

7 0
3 years ago
the distance between two successive troughs of wave is 0.4m. If the frequency of the source is 825Hz, calculate the speed of the
neonofarm [45]

Answer:

speed=330m/s

Explanation:

the speed of wave is given as

speed(meter per second) =frequency(hertz) * wavelength(meters)

so using the above formula we substitute the figures given in the question in the formula we get

speed = 0.4*825

speed =330m/s

note m/s is the si unit for speed which is read as meter per second

therefore speed =330m/s

7 0
3 years ago
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