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3 years ago

6

Help plzzz, if a question has more than one answer, pur both letters! Plzz I need 5 letters, this is the third time I’m posting

this for help, someone plzzzz help!!

1 answer:

Kaylis [27]3 years ago

4 0

Answer:

1) e

2)c

3)b

4)d

i dont know if these are right, but something along these lines if you understand the pattern

Explanation:

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How does the mass of an object affect the outcome when an unbalanced force acts on it?

Margarita [4]

Answer:

By Newton's second law, it reduces the magnitude of the acceleration, without changing its direction.

F = unbalanced force

m = mass

a = acceleration

a = F/m

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3 years ago

The velocity v of a particle moving in the xy plane is given by v = (6.0t -4.0t2 )i + 8.5j, in m/s. Here v is in m/s and t (for

atroni [7]

Answer:

Explanation:

Given

Velocity of the particle in vector form is given by

$v=\left ( 6t-4t^2\right )\hat{i}+8.5\hat{j}$

acceleration is rate of change of velocity thus acceleration is

$a=\frac{\mathrm{d} v}{\mathrm{d} t}$

$a=(6-8t)\hat{i}+0\hat{j}$

at $t=3\ s$

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4 years ago

HELP ME ANSWER THIS PLZ I WILL GIVE BRAINLIEST

disa [49]

Answer:

In mitosis, the products are identical to the parent cell, while in meiosis the products are different from the parent cell.

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3 years ago

For a damped simple harmonic oscillator, the block has a mass of 1.2 kg and the spring constant is 9.8 N/m. The damping force is

ArbitrLikvidat [17]

Answer:

a) t=24s

b) number of oscillations= 11

Explanation:

In case of a damped simple harmonic oscillator the equation of motion is

m(d²x/dt²)+b(dx/dt)+kx=0

Therefore on solving the above differential equation we get,

x(t)=A₀ $e^{\frac{-bt}{2m}}cos(w't+\phi)=A(t)cos(w't+\phi)$

where A(t)=A₀ $e^{\frac{-bt}{2m}}$

A₀ is the amplitude at t=0 and

$w'$ is the angular frequency of damped SHM, which is given by,

$w'=\sqrt{\frac{k}{m}-\frac{b^{2}}{4m^{2}} }$

Now coming to the problem,

Given: m=1.2 kg

k=9.8 N/m

b=210 g/s= 0.21 kg/s

A₀=13 cm

a) A(t)=A₀/8

⇒A₀ $e^{\frac{-bt}{2m}}$ =A₀/8

⇒ $e^{\frac{bt}{2m}}=8$

applying logarithm on both sides

⇒ $\frac{bt}{2m}=ln(8)$

⇒ $t=\frac{2m*ln(8)}{b}$

substituting the values

$t=\frac{2*1.2*ln(8)}{0.21}=24s(approx)$

b) $w'=\sqrt{\frac{k}{m}-\frac{b^{2}}{4m^{2}} }$

$w'=\sqrt{\frac{9.8}{1.2}-\frac{0.21^{2}}{4*1.2^{2}}}=2.86s^{-1}$

$T'=\frac{2\pi}{w'}$ , where $T'$ is time period of damped SHM

⇒ $T'=\frac{2\pi}{2.86}=2.2s$

let $n$ be number of oscillations made

then, $nT'=t$

⇒ $n=\frac{24}{2.2}=11(approx)$

8 0

4 years ago

4. A force of 5 N gives a mass m,, an acceleration of 10 m's, and a mass

Art [367]

Answer:

For mass m 1 newton 2nd law

F=m 1 a 1

5=m 1 ×10

m 1 = 2 1 kg

For mass m 2

F=m 2 a 2

5=m 2 ×20

m 2 = 4 1 kg

if tied together

Total mass =m 1 +m 2 = 1/2 +1/4=3/4kg

Now

F=M T Q T

a T = 5/m T = 5×4/3 = 3 /20m/s^2

Explanation:

8 0

3 years ago