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prohojiy [21]
3 years ago
13

If the original quantity is 15 and the new quantity is 19, estimate the percent change.

Mathematics
1 answer:
eduard3 years ago
5 0
To calculate percent change:
(difference between original and new)/original * 100
(19-15)/15 * 100 =
4/15 * 100 = 26.7 % increase

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John mows 247 square feet of lawn per minute. how many square yards of lawn does he mow per hour?
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6 0
4 years ago
Suppose that 71% of the surface of the Earth is covered in water, and a random number generator uses latitude and longitude to s
erik [133]

Answer:

.00059 or .0006

Step-by-step explanation:

You are trying to find what won't be in the water because there are many combinations so you use a complement formula.

1-0.79=0.29

Use the left over percentage in an equation to determine the probability.

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8 0
3 years ago
Can u please find the value of X and both missing angle measures? It’s just notes I was absent when she explained it.
KIM [24]
Heres a tip---- if it has a square its 90 degrees if it doesnt its 180 and if its in an x shape theyre equal
8 0
3 years ago
Katie has read 32% of a book. If she has read 80 pages, how many more pages does Katie have left to read? Please explain
yawa3891 [41]
Keep note of these things before we start:
-Of is a keyword that tells us multiplication is being done
-x = total number of pages
-32% = 32/100 = .32

Okay, here we go:
32% of total number of pages = 80
.32 of x = 80
.32*x = 80
.32x = 80
.32x/.32 = 80/.32
x = 250

There are 250 pages in total in Katie's book.
To find out how many pages she has to read (y), subtract the pages read from the total:
TOTAL - PAGES READ = PAGES LEFT TO READ
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8 0
3 years ago
Have Retirement Benefits
charle [14.2K]

Answer:

(a) The probability of the intersection of events "man" and "yes" is 0.55.

(b) The probability of the intersection of events "no" and "man" is 0.10.

(c) The probability of the union of events "woman" or "no" is 0.45.

Step-by-step explanation:

The information provided is:

             Yes    No   Total

Men       275   50     325

Women  150   25      175

Total      425   75      500

(a)

Compute the probability that a randomly selected employee is a man and a has retirement benefits as follows:

P(M\cap Y)=\frac{n(M\cap Y)}{N}=\frac{275}{500}=0.55

Thus, the probability of the intersection of events "man" and "yes" is 0.55.

(b)

Compute the probability that a randomly selected employee does not have retirement benefits and is a man as follows:

P(N\cap M)=\frac{n(N\cap M)}{N}=\frac{50}{500}=0.10

Thus, the probability of the intersection of events "no" and "man" is 0.10.

(c)

Compute the probability that a randomly selected employee is a woman or has no retirement benefits as follows:

P(W\cup N)=P(W)+P(N)-P(W\cap N)=\frac{175}{500}+\frac{75}{500}-\frac{25}{500}=0.45

Thus, the probability of the union of events "woman" or "no" is 0.45.

5 0
3 years ago
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