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iris [78.8K]
3 years ago
13

In how many ways 4 books can be chosen from 8 different books and be arranged in 4 spaces on a bookshelf? ​

Mathematics
1 answer:
Trava [24]3 years ago
5 0

Answer:

hope this helps

Step-by-step explanation:

3*2 * 1 = 24 ways . It is called arrangement or permutations, while if you need to group some objects it is called combination and there we need to consider unique groups only.

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Harley bought some fabric for $3.50 per yard. If she bought 3 yards, how much did the fabric cost
Verizon [17]
$3.50 X 3 yards = $10.5
4 0
3 years ago
If you have 100$ and then lose 25$ ,what is the percent change
Keith_Richards [23]

Answer:

75 %

Step-by-step explanation:

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1$= 1%

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Nataly_w [17]
60+x=3x-70
-2x=-130
X=60.5
7 0
2 years ago
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X/7- y/5=1 solve for y
Usimov [2.4K]

Answer:

y = 5/7 x -5

Step-by-step explanation:

X/7- y/5=1

Multiply each side by 35 to clear the fractions

35(X/7- y/5) =1*35

5x - 7y = 35

Subtract 5x from each side

5x-5x-7y = -5x+35

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Divide each side by -7

-7y/-7 = -5x/-7 +35/-7

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4 0
3 years ago
Read 2 more answers
Use f’( x ) = lim With h ---> 0 [f( x + h ) - f ( x )]/h to find the derivative at x for the given function. 5-x²
beks73 [17]
<h2>Answer:</h2>

The derivative of the function f(x) is:

                 f'(x)=-2x

<h2>Step-by-step explanation:</h2>

We are given a function f(x) as:

f(x)=5-x^2

We have:

f(x+h)=5-(x+h)^2\\\\i.e.\\\\f(x+h)=5-(x^2+h^2+2xh)

( Since,

(a+b)^2=a^2+b^2+2ab )

Hence, we get:

f(x+h)=5-x^2-h^2-2xh

Also, by using the definition of f'(x) i.e.

f'(x)= \lim_{h \to 0} \dfrac{f(x+h)-f(x)}{h}

Hence, on putting the value in the formula:

f'(x)= \lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-(5-x^2)}{h}\\\\\\f'(x)=\lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-5+x^2}{h}\\\\i.e.\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2-2xh}{h}\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2}{h}+\dfrac{-2xh}{h}\\\\f'(x)=\lim_{h \to 0} -h-2x\\\\i.e.\ on\ putting\ the\ limit\ we\ obtain:\\\\f'(x)=-2x

      Hence, the derivative of the function f(x) is:

          f'(x)=-2x

3 0
3 years ago
Read 2 more answers
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