Shuffle (A[1..m], B[1..n], C[1..m+n]):
Shuf[0, 0] ← True
for j ← 1 to n
Shuf[0, j] ← Shuf[0, j − 1] ∧ (B[j] = C[j])
for i ← 1 to n
Shuf[i, 0] ← Shuf[i − 1, 0] ∧ (A[i] = B[i])
for j ← 1 to n
Shuf[i, j] ← False
if A[i] = C[i + j]
Shuf[i, j] ← Shuf[i, j] ∨ Shuf[i − 1, j]
if B[i] = C[i + j]
Shuf[i, j] ← Shuf[i, j] ∨ Shuf[i, j − 1]
return Shuf[m, n]
The algorithm runs in O(mn) time.
I think only II contains an error.
Tricky because, syntactically, all three are correct I.M.O.
However, if the goal is to iterate as many times as lotNumLength, then statement II loops one time too many. This is known as an off-by-one error.
Answer:
01001001?01110111?01100001?01111001?00100000?01101001?01101011?01100101?01101100?01100001?01111001?00100000?01110101?01101110?01100001?01101100?01100001?01111001?00101110
Answer:
The appropriate response is "Cloud bursting".
Explanation:
- A strategy for the implementation of a program in a proprietary cloud or network infrastructure that explodes onto a public cloud if availability or production for computational power increases, could be considered Cloud bursting.
- It enables extra cloud capabilities throughout cases where additional facilities have been required.
Answer:
Pseudocode and flowchart.
Explanation:
I just got it correct.