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Wittaler [7]
3 years ago
7

Text that does not fit in a cell

Computers and Technology
1 answer:
Aneli [31]3 years ago
3 0
To make all wrapped text visibly, do the following to manually adjust the row height:<span>Select the cell or range for which you want to adjust the row height.On the Home tab, in the Cells group, click Format.<span>Under Cell Size , do one of the following: To automatically adjust the row height, click AutoFit Row Height.</span></span>
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Paraphin [41]

Course descriptions.

5 0
3 years ago
A datagram network allows routers to drop packets whenever they need to. The probability of a router discarding a packetis p. Co
tresset_1 [31]

Answer:

a.) k² - 3k + 3

b.) 1/(1 - k)²

c.) k^{2}  - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }

Explanation:

a.) A packet can make 1,2 or 3 hops

probability of 1 hop = k  ...(1)

probability of 2 hops = k(1-k)  ...(2)

probability of 3 hops = (1-k)²...(3)

Average number of probabilities = (1 x prob. of 1 hop) + (2 x prob. of 2 hops) + (3 x prob. of 3 hops)

                                                       = (1 × k) + (2 × k × (1 - k)) + (3 × (1-k)²)

                                                       = k + 2k - 2k² + 3(1 + k² - 2k)

∴mean number of hops                = k² - 3k + 3

b.) from (a) above, the mean number of hops when transmitting a packet is k² - 3k + 3

if k = 0 then number of hops is 3

if k = 1 then number of hops is (1 - 3 + 3) = 1

multiple transmissions can be needed if K is between 0 and 1

The probability of successful transmissions through the entire path is (1 - k)²

for one transmission, the probility of success is (1 - k)²

for two transmissions, the probility of success is 2(1 - k)²(1 - (1-k)²)

for three transmissions, the probility of success is 3(1 - k)²(1 - (1-k)²)² and so on

∴ for transmitting a single packet, it makes:

     ∞                             n-1

T = ∑ n(1 - k)²(1 - (1 - k)²)

    n-1

   = 1/(1 - k)²

c.) Mean number of required packet = ( mean number of hops when transmitting a packet × mean number of transmissions by a packet)

from (a) above, mean number of hops when transmitting a packet =  k² - 3k + 3

from (b) above, mean number of transmissions by a packet = 1/(1 - k)²

substituting: mean number of required packet =  k^{2}  - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }

6 0
3 years ago
Security measures are sometimes described as a combination of physical, technical, and administrative (PTA) safeguards. Which of
attashe74 [19]

Answer:

Measures including device data encryption, anti-malware software, and communications encryption.

6 0
4 years ago
For the past five days, the Howard family has traveled these miles: 389;126;419;93; and 394. Find the range and how. Show all yo
Fofino [41]
The answer is 326.

Range is found by subtracting the smallest number in the data set from the largest number.

Highest number: 419
Lowest number: 93

419-93
=326

(Next time make sure to post this under the Mathematics section.)
5 0
3 years ago
What does IP stand for (as in IP address)? Also, what is overtype mode?
tino4ka555 [31]
An  IP address is mostly for your WIFI . Internet Protocol . 

Overtype Mode is where you are making changes to text (putting in new characters) 
4 0
3 years ago
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