What is the measure of one angle in a regular 16-gon?
2 answers:
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Answer:
(c) 4 small squares
Step-by-step explanation:
Given
<u>Small Square:</u>
<u>Large Square:</u>
i.e. twice as long as the small square
Solving (a): The area of the small square.
This is calculated as
So, we have:
Solving (b): The area of the large square.
This is calculated as
So, we have:
Solving (c): Number of small square to cover the large square
To do this, we simply divide their areas.
Let n represents the required number; n is calculated as:
<em>Hence, 4 small squares is required to cover the large square</em>
Answer:
89.0°
Step-by-step explanation:
The segment from the centre of the circle to the chord is a perpendicular bisector, hence
third side of right triangle = 12.7 ÷ 2 = 6.35
The angle subtended at the centre by arc CD is twice the angle subtended by the right triangle at the centre
The triangle from the centre to C is congruent to the triangle from the centre to D
Calculate the angle (Θ ) in the right triangle using the sine ratio
sinΘ = =
Θ = (
) ≈ 44.5°
Hence
measure of CD = 2 × Θ = 2 × 44.5 = 89.0°