Answer:
Incomplete question
Step-by-step explanation:
What error did the student most likely make? The student multiplied by 6 instead of 10. The student multiplied by 10 instead of 6. The student used the ratio of 1:4,000 instead of 2:4,000. The student used the ratio of 2:2,000 instead of 1:2,000.
When the student multiply by 6 instead of 10
Let say the value he wanted to mulipty is x
Then the true value is 10x
Then the measure value is 6x
%error= |measure value-true value|/ true value × 100
%error=|6x-10x|/10x ×100
%error= 4x/10x × 100
%error= 40%
When he was suppose to multiply by 6, he then multiply by 10.
Let say the value he wanted to multiply is x
Then the true value is 6x
Then the measure value is 10x
%error= |measure value-true value|/ true value × 100
%error=|10x-6x|/6x ×100
%error= 4x/6x × 100
%error= 66.67%
When the student suppose to do 2:4000, he did 1:4000
The let assume what he want to find it's ration is y
The true value is 2:4000 of y
True value= 2/4000×y
True value =y/2000
Then measure value 1:4000 of y
Measure value = y/4000
%error=|measure value - true value|/ true value × 100
%error= (y/2000-y/4000)/y/2000 ×100
%error= y/4000/y/2000×100
%error= 2000/4000×100
%error= 50%
The student use 2:2000 instead of 1:2000
The let assume what he want to find it's ration is y
The true value is 1:2000 of y
True value= 1/2000×y
True value =y/2000
Then measure value 2:2000 of y
Measure value = 2y/2000
%error=|measure value - true value|/ true value × 100
%error= (2y/2000-y/2000)/y/2000 ×100
%error= y/2000/y/2000×100
%error= 2000/2000×100
%error= 100%
Doubled
